The answer is 125,65 g.
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
sulfur
44.4
0,806 mol of the element potassium (K) is equal to 31,51 g.
1.5 g Fe times 55.8 g Fe (mass number) = .027 mol (in sig figs)
The mass of iron depends on how much is present.
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
sulfur
Molar mass is the mass in grams of 1 mol of subatace, idk if that helps
The molar mass of iron is 55.845g per mol. Molar mass is the mass of a given substance divided by its amount of substance.
20.17 g/mol
44.4
To determine the molar mass for any compound, you multiply the molar mass of each element (atomic mass in grams) times its subscript, which represents the number of atoms of that element. Then add the result for each element. Molar Mass of P4S3 (4 atoms x 30.974g/mol P) + (3 atoms x 32.06g/mol S) = 123.90g/mol P + 96.18g/mol S = 220.08g/mol P4S3
0,806 mol of the element potassium (K) is equal to 31,51 g.
The molar mass of the element potassium is 39 g/mol.
According to the periodic table, the atomic mass of rubidium, Rb is 85.5. This is numerically equal to the molar mass in g/mol. Therefore the mass of 1 mol of Rb is 85.5g.Mass of 1 mol means the molar mass of the element. Molar mass of Rubidium is 85.47 gmol-1. Rb is in the 1st group.
40*0.561=22.44g