1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2
4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2
Halogens are considered to be diatomic molecules. They exist in gas (F2, Cl2), liquid (Br2) and solid phase (Iodine I2).
H2o
it is a non-polar covalent bond.therefore, the force between the molecules is known as the London dispersion force.
10
NaCl is ionically bonded with stong electrostatic attractions whereas Cl2 only has weak Van Der Waals' forces acting between the molecules More strength is needed to break NaCl's bonds than CL2's bonds. Therefore, NaCl is solid and Cl2 is a gas Hope this helps :)
Amount of Br2 = mass of sample / molar mass = 160 / 2(79.9) = 1.00mol
The mass of 0.030 moles of Br2 is 4.79424 grams, properly rounded to 4.8 grams.
because water is highly polar and Br2 is non-polar so the molecules in the water are more attracted to each other. But methylene chloride is non-polar so its molecules are no more strongly attracted to other methylene chloride molecules than they are to Br2 molecules. Since all of the forces are weak, the substance can dissolve.
9.92kg
Bromine, Br2, is a diatomic molecule that is liquid.
C2H2 + 2Br2 = C2HEBr2
Diatomic molecules. H2, F2, I2, O2, Br2 and so on.
9 moles of bromine contain 54,2.10e23 molecules.
Halogens are considered to be diatomic molecules. They exist in gas (F2, Cl2), liquid (Br2) and solid phase (Iodine I2).
there are 7 : H2 N2 O2 F2 Cl2 Br2 & I2
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
Br2 + CaI2 ----> CaBr2 + I2 bromine and iodine are diatomic molecules