You need to get the Moles of CO2 first. 9.3 g. CO2/44 g CO2= .211 mol
Then just put it into the ideal gas law at STP. PV=nRT
1.0 ATM x P = (.211 mol) (.08206) (273.15 k)---->"Plug and Chug"
P = (.211 mol) (.08206) (273.15 k) / 1.0 ATM
P= 4.7 L ---> 4,700 mL
Use the ideal gas law: PV=nRT
P= 1.00 ATM
V= 6.2 L
n= # of moles
R= .0821 (constant)
T= 273 K
1.00(6.20)=n(.0821)273
n= .277 moles CO2
According to Hyperphysics, at STP, carbon dioxide gas has a density of 0.001977g/mL
Divide the given mass by the known density.
6.5g / 0.001977g/mL = 3287.8mL*
*With correct significant figures, the answer should be rounded to 3300mL
(CO2)= 44 g/mol =molar weight
6.5g =mass
1L=1000ml
1mole=22.4L
n=m/mw 6.5g/44g/m=0.148mol CO2 = ( 0.148mole) (22.4L/1mole) (1000ml/1L) =3310ml
The volume of carbon dioxide is 3 288 mL.
6.23 moles x 44 grams/mole = 274.12 grams
CO2(g)
It depends on temperature and pressure. Assuming 25.0ºC and 1.00 atmospheres then 125 g CO2 occupies 54.7 dm3.
co2 and h2 gases
5126 cm3
The volume is 1,1 mL.
CO2(g)
It depends on temperature and pressure. Assuming 25.0ºC and 1.00 atmospheres then 125 g CO2 occupies 54.7 dm3.
The mass is 10 727 kg.
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
The volume of CO2 is 53,18 litres.
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
co2 and h2 gases
CO2 floats because its density is less then water. Anything will float if its density is less then water. That is; when a certain volume of CO2 (or anything else) weighs less then the same volume of water.
61ml
This is a mass-mole conversion problem and a gas law problem all rolled into one! First, let's figure out how many moles of CO2 we have. CO2 has 44 grams to the mole, according to the periodic table. If you set up a direct proportion with the given mass, 10.0g, you get 0.23 moles of CO2. Second, figure out what volume 0.23 moles of CO2 will occupy at standard temperature and pressure. Every gas occupies 22.4 liters of space at STP, so 22.4 liters x 0.23 moles = 5.15 liters at STP. Third, convert all temperatures to degrees Kelvin. 27 Celsius = 300 Kelvin, and 0 Celsius (from STP) = 273 Kelvin. Finally, use the gas laws. Set up a direct proportion between the STP volume and temperature and the given temperature, with the new volume as the unknown. Temperature and volume share a direct relationship: 5.15/273=x/300. Solving for x gets you 5.66 liters, which is the answer.
5126 cm3
22.4 liters at STP