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A properly written formula for the compound, using the subscript fonts available for answers but not for questions, is Al2(SO4)3. This formula shows that there are 2 aluminum atoms, three sulfur atoms, and twelve oxygen atoms in each formula unit, for a total of 342.14 grams per formula unit. 647 of these formula units will have a mass of 647 X 342.14 gramsor 221 kilograms, to the justified number of significant digits.
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What is the formula name for Aluminum sulfate?
Aluminum sulfate is formulated by Al2(SO4)3
How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
What is the balanced chemical equation of iron metal added with aluminum sulfate solution?
3Fe (s) + Al2(SO4)3 (aq) → 3Fe(SO4) (aq) + 2Al (s)
The formula for aluminum sulfate is Al2 SO4 3 figure the molar mass of aluminum sulfate to the nearest gram?
342
What is the empirical formula for aluminum sulfate?
Al2(SO4)3
How many moles of sulfur are present in 3.5 moles of Al2 SO4?
Al2 SO4(wrong) this is how it should be written Al2(SO4)3This how you do it3.5 moles Al2(SO4)3 x 3 mole Sulfur / 1 moles Al2(SO4)3 = put that in ur calculator it will give u the answer
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
What is the formula name for Aluminum sulfate?
Aluminum sulfate is formulated by Al2(SO4)3
How many moles of nitrogen are in 2.5 10 -2 moles of quinine?
how many moles of sulfur are present in 3.4 moles of Al2(SO4)3
Aluminium sulphate formula?
Formula: Al2(SO4)3
How do you find out how many oxygen atoms are in 4.70 g of Al2 SO4 3?
How many moles are in 4.70g of NH3?
What is the chemical formula for aluminium sulphide?
The formula for the anhydrous form is Al2(SO3)3.
What is the molar weight for aluminum sulfate?
Al2(SO4)3 [anhydrous] = 342,15 Al2(SO4)3 [octadecahydrate] = 648,41
How many moles of Aluminum Sulfate are present when 0.12 moles of each compound is dissolved in water?
Well...Since Aluminum is insoluble in water as an element I assume you mean that an 0.12 mol Aluminum ions react with 0.12 mol Sulfate ions to form x mol of Aluminum Sulfate. Balanced equation (Kinda since since the other portions of the compounds are unknown): 2 Al3+(aq) + 3 SO42-(aq) <----->Al2(SO4)3 (aq) 0.12mol*(1mol Al2(SO4)3 (aq)/2mol Al3+)=0.06mol Al2(SO4)3 (aq) 0.12mol*(1molAl2(SO4)3/3mol SO42-) =0.04mol Al2(SO4)3 (aq) *Answer*
How many grams of aluminum sulfate are produced from 2.67 mol sulfuric acid With the balanced equation Al2O3 3H2SO4 -- Al2 (SO4)3 3H2O?
Al2O3 + 3H2SO4 = Al2 (SO4)3 + 3H2O We note that the molar ratios are 1:3::1:3 By Equivalence 0.89 : 2.67 ;; 0,89 :2.67 So moles of aluminium sulphate produced is 0.89 Using the equation moles = mass(g) / Mr Then mass = moles X Mr Refer to the Atomic Masses in the Periodic Table to find the Mr(Relative Molecular mass of Al2(SO4)3 Hence Al x 2 = 27 x 2 = 54 S x 3 = 32 x 3 = 96 O x (4 x 3 = 12) 16 x 12 = 192 54 + 96 + 192 = 342 ( Mr of Al2(SO4)3 ) Hence mass(g) = 0,89 X 342 = 304.38 g (This is the 100% theoretical yield. Experimentally it will be less , owing to losses in the filter paper , spillages etc., )
What is AL2(SO4)3?
Aluminum Sulfate
What is the balanced chemical equation of iron metal added with aluminum sulfate solution?
3Fe (s) + Al2(SO4)3 (aq) → 3Fe(SO4) (aq) + 2Al (s)
