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How can calculate recoil velocity of gun?
The recoil velocity of a gun can be calculated using the principle of conservation of momentum. The formula to calculate the recoil velocity is: Recoil velocity = (mass of bullet * velocity of bullet) / mass of gun. This formula takes into account the mass of the bullet, the velocity of the bullet, and the mass of the gun.
A bullet is fired from a gun. The speed of the bullet will be about the same as the speed of the recoiling gun if the mass of the bullet equals the mass of the gun?
The mass of a bullet is nowhere near the mass of a gun. A bullet weighs at most a few hundred grains. Most guns weigh at least a couple of pounds, some weigh several pounds (talking about handguns and rifles).
What is the distance from England to Bangladesh?
2mm 2mm
Why a force of returning of the rifle is smaller than that of the bullet?
The force of the rifle returning back after firing a bullet is smaller than the force on the bullet because the rifle has a larger mass compared to the bullet. According to Newton's third law, force is equal to mass times acceleration, so the force exerted on the rifle is smaller due to the larger mass and slower acceleration compared to the bullet.
When a rifle is fired how does the size of the force of the rifle on the bullet compare with the force of the bullet on the rifle how does the acceleration of the rifle compare with that of the bullet?
The force of the rifle on the bullet and the force of the bullet on the rifle are equal in magnitude but opposite in direction, according to Newton's third law of motion. However, the mass of the rifle is much larger than the mass of the bullet, so the acceleration of the rifle is much smaller compared to the acceleration of the bullet.
What is the wing span of an American eagle owl?
2mm 2mm
What is thicker 6mm or 2mm?
6mm is thicker than 2mm. It has a greater thickness of 4mm.
How do you apply the concept of momentum to compare the mass and velocity of a slow moving train and of a high-speed bullet?
The momentum of an object is the product of its mass and velocity. In the case of a slow moving train and a high-speed bullet, the bullet would have a higher momentum due to its higher velocity even if its mass is smaller. This is because momentum is more affected by velocity than by mass.
How can the concept of momentum compare to a slow moving train and a high speed bullet?
Momentum is the product of an object's mass and velocity. A high-speed bullet has more momentum than a slow moving train because the bullet has a smaller mass but much higher velocity. This means the bullet can have more impact and be harder to stop compared to the train, even though the train has more mass.
What is the mass of a bullet?
Depends on the composition of the bullet. If it's 100% lead and at STP and 1 G it's mass and weight will be about the same. Move it anywhere where the gravitational force is more or less than 1G and the weight will chance but the mass will remain the same. Lead bullets contain antimony as a hardener...so the mass of a real bullet differs from that described above.
What form of energy does a speeding bullet have?
A speeding bullet has kinetic energy, which is the energy associated with its motion. As the bullet travels, it carries this kinetic energy due to its velocity and mass.
A rifle is fired and you are able to measure both the muzzle velocity of the bullet as well as the recoil velocity of rifle how do you explain the fact that the forward velocity of the bullet is great?
The force exerted on the bullet and the recoil force against the rifleman, are equal to each other (for every action there is an equal and opposite reaction). The bullet has a very small mass, and the rifle/rifleman possess a large mass, force is equal to one half mass times velocity squared, F=m/2*v^2. So velocity of the bullet is the square root of twice force divided by mass, small mass equals large velocity. Another way of looking at this problem is to invoke the law of the conservation of momentum: mass(bullet)*muzzle_velocity(bullet) = mass(rifle)*recoil_velocity(rifle). This is an approximation that neglects the momentum carried away the propellant (both spent and unburned) that exits the muzzle after the bullet.
