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Velocity = Distance / Time= 6000m / 10s= 600 m/s= 1342.2 miles per hour= 22.369 miles per minute= 1166.3 knots= 1968.5 feet per second
NO!!! Acceleration is the change in velocity over a give time. A = ( u - v) / t e.g. A cae standing start to 30 mph. in say 10 secs. First we need to change the units of time and distance . 30 mph = 44 m/s u = final velocity of 44 m/s v = initial velocity of 0 m/s ( standing start) t = 10 secs. Substitute a = ( 44 m/s - 0 m/s_ / 10s a = 44m/r /10s a = 4.4 m/s^2 Bear in mind gravitational acceleration on Earth is ~ 10m/s^2
You use the equation d = vit + 1/2at2, where d is distance or displacement, vi is initial velocity (0), t is time, and a is acceleration. d = (0)(10s) + (1/2)(9.8m/s2)(10s)2 = 0 + 490m = 490m The answer above does not take into account air friction or the possibility that the rock will hit the walls of the shaft and slow down due to that friction. Air friction will shorten the distance by perhaps 15% to 30% depending, among other things on the shape and mass of the rock, retardation due to hitting the shaft walls is unpredictable.
acceleration is the change in velocity by change in time (often meters/second/second). so, if a car was travelling 10m/s and ten seconds later, it is travelling 20m/s in the same direction, the acceleration would be (20m/s-10m/s)/10s=1m/s/s. with a constant velocity the change in velocity is zero (x m/s - x m/s)/y s=0m/s/s and acceleration is also zero.
3000m/s
5m/s
First, you must find the acceleration. You can do so using the following kinematics equation: V=V0+at (V is the final velocity, Vo is the initial velocity, a is acceleration and t is time.) The object ends up stopping, so V = 0. V0 is given as 4 m/s and t is given as 10s. So: 0 = 4m/s + a(10s) -4m/s = a(10s) (-4m/s)/(10s) = a -0.4m/s2 = a Now you can use Newton's Second Law equation to find the force. F=ma (F is force, m is mass, and a is acceleration.) Mass is given as 80kg, and the acceleration has been calculated to be -0.4m/s2. F=(80kg)(-0.4m/s2) F= -32 N
mass of the railroad car =2000kgvelocity=15m/stime=10s:.Force applied to stop the railroad car=mass X acceleration=mass X velocity/time=2000 X 15 / 10=30000 NSo, the force applied is 30000 N.
Velocity = Distance / Time= 6000m / 10s= 600 m/s= 1342.2 miles per hour= 22.369 miles per minute= 1166.3 knots= 1968.5 feet per second
ok i get this
there are 7 tenths in 275 or 2.75 10s
By Newton second law, F=ma; 20=5*a; or a=4m/s/s. initial velocity=0 and time=10s so by first equation of motion V=0+at, so V=4*10=40m/s, so kinetic energy of body=K.E=1/2*m*V2 = 0.5*5*1600=25*160=.....
NO!!! Acceleration is the change in velocity over a give time. A = ( u - v) / t e.g. A cae standing start to 30 mph. in say 10 secs. First we need to change the units of time and distance . 30 mph = 44 m/s u = final velocity of 44 m/s v = initial velocity of 0 m/s ( standing start) t = 10 secs. Substitute a = ( 44 m/s - 0 m/s_ / 10s a = 44m/r /10s a = 4.4 m/s^2 Bear in mind gravitational acceleration on Earth is ~ 10m/s^2
There are 8 10s in 85, with 5 left over.
Sadly, the phrase "10s to 76w longitude" is quite meaningless.-- As soon as you say "10s" or "10 south", that's the latitude.-- 10s/76w is the latitude and longitude of a point. The point isin central Peru, about 165 miles northeast of the center of Lima.
600
600