It depends on the specification of the PLC. One with a fanout of 10 into a standard TTL load can sink 16 milliamps and source 4 milliamps.
The rating is about 1500W. This is for both the input and the output. Output voltage is usually 2,000 volts. Divide watts by input volts to get input current. And divide watts by output voltage to get output current. -Joe
The kva rating includes the power factor of the connected load.KW * Power Factor = kva.AnswerThe above answer is incorrect, as it's actually kV.A x power factor = kW.The answer is straightforward, the output of the UPS is the product of its rated output voltage and its rated output current, and the product of voltage and current is 'apparent power', expressed in volt amperes.
As long as you don't exceed the current rating of the cable.
Input and output voltages, maximum current rating, often expressed in VA or kVA as the voltage rating times the current rating. Operating frequency is the next important parameter because if the frequency is lower, the voltage must be reduced in proportion.
It is the rated maximum current that can be taken from the transformer. This is equal to the VA rating divided by the output voltage. So a 6 kVA 240 v transformer would have a maximum current rating of 6000/240 or 25 amps.
Yes, but your input current is going to be high at 133 amps. The output of the transformer is not going to be 16 KVA, that is the rating of the transformer.
Divide the output rating by the input rating
By reducing the output fusing of a generator, the total output of the generator will also be reduced. The capacity of the generator will remain the same but the fault trip point will be lowered.
By reducing the output fusing of a generator, the total output of the generator will also be reduced. The capacity of the generator will remain the same but the fault trip point will be lowered.
The kva rating includes the power factor of the connected load.KW * Power Factor = kva.AnswerThe above answer is incorrect, as it's actually kV.A x power factor = kW.The answer is straightforward, the output of the UPS is the product of its rated output voltage and its rated output current, and the product of voltage and current is 'apparent power', expressed in volt amperes.
This is the rated output of the transformer, obtained by multiplying the rated secondary voltage by the rated secondary current. And it's 'kV.A', not 'kva'.
It depends on the current rating of the armature winding, which will determine its input power. It's output power then depends on the motor's efficiency.