P=VI=I*R*I=I^2 R
P=2 therefore I^2 =2/100
I=SQRT(1/50) = 0.14142 amps
If a 100 ohm 1 watt resistor and an 800 ohm 2 watt resistor are connected in series, the maximum DC voltage that can be applied without exceeding the power limit of both resistors is 45 volts. Start with power rule and ohm's law... P = IE E = IR so P = I2R solve for current I2 = P/R I = (P/R)0.5 determine current at max power for each resistor R1 = 100, R2 = 800 I1 = (1/100)0.5 = 0.1 amperes I2 = (2/800)0.5 = 0.05 amperes The limiting resistor is R2, so calculate voltage of both at current flow of I2 V1+2 = (0.05)(900) = 45 volts
Without load there is no current so it is impossible to measure it.
A resistor is a material that attenuates the current through a conductor. An insulator isolates the conductor from the surrounding material.
LED's are light emmitting diodes. diodes have a voltage threshold that must be reached for them to fully "turn on". A resistor can be used to limit that voltage. As the voltage drop across the diode is increased above the turn on voltage (typically .5 - .7 volts), the diode will emmit light. The LED will only light up so far, so by turning the voltage up significantly more will have a very limitted payback in light output.
To lower the voltage and amperage in order to better fit the needs of other components.
There is no direct relationship.Power ('wattage') is a measure of the rate at which the resistor can dissipate energy; excessive power means that a resistor cannot dissipate energy fast enough to prevent its temperature becoming excessive -excessive enough to damage the resistor.As the rate at which a resistor can dissipate energy is determined by its physical size, a resistor's power rating(maximum continuous power it can handle without exceeding its rated temperature) depends on the physical size of the resistor.On the other hand, the resistance of a resistor is notaffected by its physical dimensions, as a resistor can be manufactured to any particular value of resistance for whatever physical size is necessary to achieve its rated power.If you know a resistor's rated power and its resistance, then you can calculate the maximum continuous current that resistor can handle without overheating (using the equation: power = current squared x resistance).
If a 100 ohm 1 watt resistor and an 800 ohm 2 watt resistor are connected in series, the maximum DC voltage that can be applied without exceeding the power limit of both resistors is 45 volts. Start with power rule and ohm's law... P = IE E = IR so P = I2R solve for current I2 = P/R I = (P/R)0.5 determine current at max power for each resistor R1 = 100, R2 = 800 I1 = (1/100)0.5 = 0.1 amperes I2 = (2/800)0.5 = 0.05 amperes The limiting resistor is R2, so calculate voltage of both at current flow of I2 V1+2 = (0.05)(900) = 45 volts
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
Without load there is no current so it is impossible to measure it.
The current can't be calculated from the information given in the question.The power rating of a resistor is the maximum power it can dissipate before it overheatsand its resistance possibly changes permanently. The power rating is not the amount ofpower it always dissipates.So, all we really know about the resistor in the question is that its resistance is 21 ohms.And all we can say about the current through it is:Current through the resistor = (voltage between the ends of the resistor) divided by (21).
Depends on the current. Put a resistor in-line with the current, then measure the voltage across the resistor. V=RI. So, divide the measured voltage by resistor value. Be careful with the size of the resistor, as Power dissipated in a resistor is R*I^2 or V^2/2. So, a 1-Amp current into a 1 Ohm resistor will result in a 1Watt power dissipated in the resistor. If it's too small, it'll burn. Also, notice that if you do that, you haven't measured the current in the original circuit. You've measured the current when an extra resistor is installed in the original circuit, and that's different.
What is the current running through resistor four?1 amps..!What is the current running through resistor one? 3 amps...!What is the current running through resistor three? 2amps..!What is the current running through resistor five? 3 amps..!What is the voltage drop running through resistor five? 45 volts...!What is the equivalent resistance through the parallel portion of the circuit? 6 ohmsAnswerA resistor is a conductor, albeit one with a higher resistance than a length of wire, so current passes through it without any problem. The magnitude of the current will, of course, be somewhat lower because of the additional resistance.
Maximum power rating describes the maximum power at which a device can operate without reaching an excessive temperature. For example, in the case of a resistor, if its maximum power rating is exceeded, then it may burn out.
A resistor is a material that attenuates the current through a conductor. An insulator isolates the conductor from the surrounding material.
LED's are light emmitting diodes. diodes have a voltage threshold that must be reached for them to fully "turn on". A resistor can be used to limit that voltage. As the voltage drop across the diode is increased above the turn on voltage (typically .5 - .7 volts), the diode will emmit light. The LED will only light up so far, so by turning the voltage up significantly more will have a very limitted payback in light output.
To lower the voltage and amperage in order to better fit the needs of other components.
Don't follow what a '2200watt resistor' is. A resistor spec is measured in ohms. Ohms Law is expressed as: Voltage drop = current x resistance, and the wattage of the resistor is = volts drop x current. You have to decide if your resistor is 2200 ohms, or is taking 2200 watts. These two alternatives will give different results for the current. If it is 2200 watts, at 110 volts, the current is 20 amps. If it is 2200 ohms, at 110 volts, the current will be 50 milliamps. (0.05amps)