First of all, it is HCl solution, more properly hydrochloric acid (that is HC l ). It is composed of hydrogen (H) and chlorine (Cl).
The answer depends on the volume of the acid and the concentration of the alkali. Here is a sample calculation with some random values for the variables you have not given.
If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the number of moles of NaOH equals the number of moles of HCl. 25 ml is equal to 0.025 liters, and since molarity is moles per liter we have:
Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125 moles
Moles of NaOH = moles of HCl = 0.0125 moles
If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the molarity of the HCl is:
0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl
0.289 Moles is the molarity of an NaOH solution if 4.37 ml is titrated by 11.1 ml of 0.0904m hno3.
The HCL concentration is 1.2M or 1.2N
It would mean that you have use too much NaOH to titrate your solution, causing your calculated molarity to be on the higher end of the scale.
Molarity = moles of solute/Liters of solutionMolarity = 4 moles NaOH/ 2L= 2 M NaOH========
28.6ml/10ml*.175M = .5005 M then with significant figured the answer is 0.501 M
(7 mL)(X M HCl) = (27.6 mL)(0.170 M NaOH)7X = 4.692X = 0.7 M HCl==========
Molarity = moles of solute/Liters of solution Molarity = 2.5 moles NaOH/10 Liters = 0.25 M NaOH ==========
Molarity = moles of solute/volume of solution 2.24 grams NaOH (1mol/33.998g) = 0.0659 moles NaOH/0.5 liters = 0.132 Molarity of NaOH
.75 L because you multiply the L of NaOH by the Molarity of NaOH the divide it by the Molarity given of NaOH to get the volume needed
HCl + NaOH -----> NaCl + H2O
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============
Molarity = moles of solute/Liters of solutionLiters of solution = moles of solute/MolarityLiters NaOH = 3.25 moles NaOH/2.5 M NaOH= 1.30 Liters NaOH=============
95g NaOH * 1 mol NaOH/ = 2.375 mol NaOH 40g NaOH Molarity (M) = mol / L M = (2.375) / (0.450) M = 5.28
0.829 M is the molarity. The formula is: mL x M = millimoles of substance millimoles of NaOH = millimoles of HCl mL x M = mL x M 28.6 x 0.145 = 5.00 x M M = 0.829
Molarity is a measure of concentration. As an example, 1M NaOH solution contains 40g of NaOH in one litre of water (1000g) and thus the concentration would be 4% NaOH.
0.33 M NaOH solution
This depends on the mass of NaOH dissolved in 1 L water.