Acids and Bases
Chemical Equations

What is the minimum molarity of HCl when titrated with 18.6ml of NaOH?

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2016-07-13 14:05:35

First of all, it is HCl solution, more properly hydrochloric

acid (that is HC l ). It is composed of hydrogen (H) and chlorine


The answer depends on the volume of the acid and the

concentration of the alkali. Here is a sample calculation with some

random values for the variables you have not given.

If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the

number of moles of NaOH equals the number of moles of HCl. 25 ml is

equal to 0.025 liters, and since molarity is moles per liter we


Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125


Moles of NaOH = moles of HCl = 0.0125 moles

If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the

molarity of the HCl is:

0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl

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