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What is the minimum molarity of HCl when titrated with 18.6ml of NaOH?

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2016-07-13 14:05:35

First of all, it is HCl solution, more properly hydrochloric

acid (that is HC l ). It is composed of hydrogen (H) and chlorine

(Cl).

The answer depends on the volume of the acid and the

concentration of the alkali. Here is a sample calculation with some

random values for the variables you have not given.

If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the

number of moles of NaOH equals the number of moles of HCl. 25 ml is

equal to 0.025 liters, and since molarity is moles per liter we

have:

Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125

moles

Moles of NaOH = moles of HCl = 0.0125 moles

If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the

molarity of the HCl is:

0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl


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