What is the minimum molarity of HCl when titrated with 18.6ml of NaOH?
First of all, it is HCl solution, more properly hydrochloric
acid (that is HC l ). It is composed of hydrogen (H) and chlorine
The answer depends on the volume of the acid and the
concentration of the alkali. Here is a sample calculation with some
random values for the variables you have not given.
If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the
number of moles of NaOH equals the number of moles of HCl. 25 ml is
equal to 0.025 liters, and since molarity is moles per liter we
Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125
Moles of NaOH = moles of HCl = 0.0125 moles
If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the
molarity of the HCl is:
0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl