15.4 * 103 at 260 nm pH 7.5
The molar extinction coefficient (also sometimes called molar absorbtivity coefficient) is a measure of how strongly a solution of a substance absorbs light (the value depends on the particular wavelength of light used). By passing light through a solution and determining how much of the light is absorbed, you can use the path length and molar extinction coefficient to determine the concentration of the solution.Look up "Beer-Lambert law" if you want details.
Molecular mass of CO = atomic weight of O + atomic weight of C = 28,01 g
To find the percent composition of carbon in carbon monoxide (CO), we first determine the molar mass of CO. Carbon has a molar mass of approximately 12.01 g/mol, and oxygen has a molar mass of about 16.00 g/mol, giving CO a total molar mass of 28.01 g/mol. The percent composition of carbon is calculated as (molar mass of carbon / molar mass of CO) × 100%, which results in (12.01 g/mol / 28.01 g/mol) × 100% ≈ 42.8%. Thus, the percent composition of carbon in carbon monoxide is approximately 42.8%.
To find the number of moles of CO molecules in 52g of CO, we first need to determine the molar mass of CO, which is approximately 28 g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 52g of CO is equivalent to approximately 1.86 moles of CO molecules.
196.9497 g/mol
The molar mass of carbon monoxide (CO) is 28.01 g/mol. The molar mass of carbon is 12.01 g/mol. To find the mass percent of carbon in CO, you divide the molar mass of carbon by the molar mass of CO and multiply by 100. (12.01 g/mol / 28.01 g/mol) x 100 = 42.9% Therefore, the mass percent of carbon in carbon monoxide is approximately 42.9%.
To find the number of molecules in 140 g of CO (carbon monoxide), you first need to determine the number of moles of CO. The molar mass of CO is 28 g/mol. Divide the given mass by the molar mass to get the number of moles, then use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
The number of molecules of 140g of CO is 3.01x10^24 molecules of CO. CO is Carbon monoxide, with the mono meaning one. It's molar mass is 28.01 g/mol.
the co-efficient
Co-efficient
the co-efficient
This question simply does not make sense.