2.8
2.8
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
1,4 moles of CO are produced.
How many moles of atoms are contained in 382 g Co
Assuming you meant Carbon monoxide (CO): (1.5)* (6.02*10^23) = 9.03*10^23 molecules CO That could be written as: 903,000,000,000,000,000,000,000 molecules
The answer is 6,482 moles.
The equivalence is 1992 moles.
There are 6.023x10^23 molecules in one mole of a compound. So now, you have to find how many moles of each compound you have. CO's molecular weight is (12+16) = 28 g/mol N2's molecular weight is (14+14) = 28 g/mol So you find the moles of each. moles of N2 = 20g/ 28g/mol = .714 moles moles of CO = 16g / 28 g/mol = .571 moles So, N2 has (.714 *6.023x10^23) has 4.3 x10^23 molecules and CO (.571 *6.023x10^23) has 3.4x10^23 molecules. So, 20g of N2 has more molecules than 16g of CO
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
1,4 moles of CO are produced.
4,54 L of CO have 0,182 moles.
How many moles of atoms are contained in 382 g Co
Assuming you meant Carbon monoxide (CO): (1.5)* (6.02*10^23) = 9.03*10^23 molecules CO That could be written as: 903,000,000,000,000,000,000,000 molecules
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
The answer is 6,482 moles.
382 g Co contain 6,482 moles.
2,55 moles of the compound CO have 71,4 grams.
6.02x1023