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The number of molecules of 140g of CO is 3.01x10^24 molecules of CO. CO is Carbon monoxide, with the mono meaning one. It's molar mass is 28.01 g/mol.

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How many molecules of carbon monoxide are present in 3.69 grams of this compound?

To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.


How many molecules are in 25.0 g NO2?

To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.


How many oxygen molecules are there in in 4 g of oxygen?

Assuming you mean oxygen gas, the number of molecules can be found by first finding the number of moles = mass of oxygen (4g) / Molecular mass of oxygen gas (32 g mol-1) This tells us there is 0.125 mol of oxygen gas present. The number of molecules present is given by the number of moles x the avogadro constant (6.022x10^23) So the number of oxygen gas molecules present is equal to 0.125 x 6.022x10^23 = 7.5275x10^22 molecules


How many molecules of LiCl are in a 127.17 g sample?

To find the number of molecules of LiCl in a 127.17 g sample, you first need to convert the mass of LiCl to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules. Calculate the number of molecules of LiCl in the sample using these values.


How many molecules of sulfur dioxide are present in 72 g of the substance?

To determine the number of molecules of sulfur dioxide in 72 g of the substance, we first need to calculate the number of moles of sulfur dioxide present. The molar mass of sulfur dioxide (SO2) is approximately 64 g/mol. Therefore, 72 g of sulfur dioxide is equal to 72 g / 64 g/mol = 1.125 moles. Next, we use Avogadro's number, which is 6.022 x 10^23 molecules/mol, to convert moles to molecules. Therefore, there are approximately 6.78 x 10^23 molecules of sulfur dioxide in 72 g of the substance.

Related Questions

What is the number of molecule of G of CO?

The number of molecules of 140g of CO is 3.01x10^24 molecules of CO. CO is Carbon monoxide, with the mono meaning one. It's molar mass is 28.01 g/mol.


How many moles of CO molecules are in 52g CO?

To find the number of moles of CO molecules in 52g of CO, we first need to determine the molar mass of CO, which is approximately 28 g/mol. Then, we divide the given mass by the molar mass to get the number of moles. So, 52g of CO is equivalent to approximately 1.86 moles of CO molecules.


What is the number of molecules in 8 g of oxygen gas?

1) 7 g co 2)16 g so2 3)11 g co2


What is the number of molecules of 140g of co?

To find the number of molecules in 140g of CO (carbon monoxide), first calculate the number of moles using the molar mass of CO (28.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, 140g of CO corresponds to about 5 moles, which is approximately 3.01 x 10^24 molecules.


How many molecules of carbon monoxide are present in 3.69 grams of this compound?

To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.


In the gaseous state chlorine exists as a diatomic molecule Cl2 (Molar mass 70.9 gmol). Calculate the number of moles of chlorine present in 140 g of chlorine gas.?

To calculate the number of moles in 140 g of Cl2, divide the given mass by the molar mass of Cl2. Number of moles = Mass / Molar mass = 140 g / 70.9 g/mol = 1.97 moles. Therefore, there are 1.97 moles of chlorine gas in 140 g of Cl2.


If you have 4.5 X 10 24 atoms of CH4 how many grams do you have Please help and explain how you got the answer?

The molar mass of methane is 16,04 g.1 mol has 6,022 140 857.10e23 molecules. In your question the correct word is molecules not atoms.6,022 140 857.10e23---------------------------------16,04 g4,5.10e24---------------------------------------------------xx = (4,5.10e24 . 16,04)/6,022 140 857.10e23 = 119,6 g


How many molecules are in 11.2 g Ar?

To find the number of molecules in 11.2 g of Ar, you need to use Avogadro's number and the molar mass of Ar. First, find the number of moles in 11.2 g using the molar mass of Ar (39.95 g/mol). Then, convert moles to molecules by multiplying by Avogadro's number (6.022 x 10^23 molecules/mol).


How many molecules are in .75 g of ammonia?

To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.


How many molecules are in 334 g CBr4?

To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.


How many moles are present in 140.g of Cacl2?

To find the number of moles in 140 g of CaCl2, you need to divide the given mass by the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol. So, 140 g / 110.98 g/mol = 1.26 moles of CaCl2.


What is the number of molecules in 9.0 g of steam and how?

To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.