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28.01g/mol
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How many molecules are in 140gm of nitrogen gas?
140g/28 (i.e. molecular weight of 14+14) is 5 moles N2. 5x 6.022 x1023 is 3.011x1024 molecules.
How many atoms are in 1.5 moles of water (H2O)?
Assuming you meant Carbon monoxide (CO): (1.5)* (6.02*10^23) = 9.03*10^23 molecules CO That could be written as: 903,000,000,000,000,000,000,000 molecules
How many moles of CO molecules are in 52g CO?
no
How many moles are contained in 4.65 x 1024 molecules of CO?
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
Calculate the number of CO molecules in 1.1 L of this air at a pressure of 760 torr and a temperature of 18 Celsius?
Using the ideal gas law (using torr instead of atm), we calculate that there would be .046 moles of CO, or 2.7x1022 molecules of carbon monoxide.
What is the number of molecules of 140 g of CO?
The number of molecules of 140g of CO is 3.01x10^24 molecules of CO. CO is Carbon monoxide, with the mono meaning one. It's molar mass is 28.01 g/mol.
What is the number of molecule of G of CO?
The number of molecules of 140g of CO is 3.01x10^24 molecules of CO. CO is Carbon monoxide, with the mono meaning one. It's molar mass is 28.01 g/mol.
How many molecules are in 140gm of nitrogen gas?
140g/28 (i.e. molecular weight of 14+14) is 5 moles N2. 5x 6.022 x1023 is 3.011x1024 molecules.
Is the number of molecules of carbon monoxide in 1 mol CO equal to Avogadro number?
Yes.
How many CO molecules are there in a mole of CO?
6.02x1023
How many atoms are in 1.5 moles of water (H2O)?
Assuming you meant Carbon monoxide (CO): (1.5)* (6.02*10^23) = 9.03*10^23 molecules CO That could be written as: 903,000,000,000,000,000,000,000 molecules
How many moles of CO molecules are in 52g CO?
no
How many moles are contained in 4.65 x 1024 molecules of CO?
1 mole contains 6.022 x 1023 molecules. number of moles of CO= (4.65 x 1024) / (6.022 x 1023) = 7.72 mol The identity of the molecule does not change the answer.
Calculate the number of CO molecules in 1.1 L of this air at a pressure of 760 torr and a temperature of 18 Celsius?
Using the ideal gas law (using torr instead of atm), we calculate that there would be .046 moles of CO, or 2.7x1022 molecules of carbon monoxide.
How many molecules of carbon monoxide are present in 3.69 grams of this compound?
3.69 grams CO (1mol CO/28.01g CO )(6.022 X 10^23/1mol CO ) = 7.93 X 10^22 molecules
Which Molecules contains a polar covalents bond O2 CO H2 N2?
CO
Is 8oz equal to 140g?
That is 226.796 gm
