The chemical formula for calcium hydroxide is Ca(OH)2.
Ca: 40.08
O: 16.00
H: 1.01
Molar mass= 74.10 g Ca(OH)2
56.08
No, because one mole of calcium hydroxide constitutes two equivalents of calcium hydroxide for neutralization, but one mole of phosphoric acid constitutes three equivalents of phosphoric acid for neutralization. Therefore, one mole of calcium hydroxide will neutralize only 2/3 of one mole of phosphoric acid.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
Quite a few! 175 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca) = 2.63 X 10^24 atoms of calcium -------------------------------------------
It depends on what it is reacting with.
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
No, because one mole of calcium hydroxide constitutes two equivalents of calcium hydroxide for neutralization, but one mole of phosphoric acid constitutes three equivalents of phosphoric acid for neutralization. Therefore, one mole of calcium hydroxide will neutralize only 2/3 of one mole of phosphoric acid.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
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Quite a few! 175 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca) = 2.63 X 10^24 atoms of calcium -------------------------------------------
129 grams calcium (1 mole Ca/40.08 grams calcium)(6.022 X 10^23calcium atoms/1 mole Ca) = 1.94 X 10^24 atoms of calcium
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
34.5 g CaCO3 (1 mole CaCO3/100.09 g)(1 mole Ca/1 mole CaCO3)(40.08 g/1 mole Ca) = 13.8 grams calcium ===============
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
It depends on what it is reacting with.
Quite a few! 147 grams calcium (1 mole Ca/40.08 grams)(6.022 X 1023/1 mole Ca) = 2.21 X 1024 atoms of calcium ----------------------------------------
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------