The chemical formula for calcium hydroxide is Ca(OH)2.
Ca: 40.08
O: 16.00
H: 1.01
Molar mass= 74.10 g Ca(OH)2
No, because one mole of calcium hydroxide constitutes two equivalents of calcium hydroxide for neutralization, but one mole of phosphoric acid constitutes three equivalents of phosphoric acid for neutralization. Therefore, one mole of calcium hydroxide will neutralize only 2/3 of one mole of phosphoric acid.
To determine the grams of calcium sulfate formed from 130 grams of calcium hydroxide (Ca(OH)₂), we first need to calculate the moles of Ca(OH)₂. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol, so 130 g corresponds to about 1.76 moles. The balanced chemical equation for the reaction with sulfuric acid (H₂SO₄) produces one mole of calcium sulfate (CaSO₄) for each mole of calcium hydroxide. Therefore, 1.76 moles of Ca(OH)₂ will yield 1.76 moles of CaSO₄, which is approximately 246.5 grams (using the molar mass of CaSO₄, about 136.14 g/mol).
It depends on what it is reacting with.
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
The density of calcium is 1.55g/cc (1.55 grams per cubic centimeter). The mass depends on how large the quantity of calcium is.
The reaction between calcium carbide and water produces acetylene gas (C2H2) and calcium hydroxide (Ca(OH)2. When 1 mole of calcium carbide reacts with 2 moles of water, it produces 1 mole of acetylene and 1 mole of calcium hydroxide. The molar mass of calcium carbide is 64.1 g/mol, so the reaction would produce 26.04 grams of acetylene gas and 74.1 grams of calcium hydroxide from every 64.1 grams of calcium carbide reacted.
To neutralize calcium hydroxide, the molar ratio is 2:1 (2 moles of boric acid for every 1 mole of calcium hydroxide). Calculate the molar mass of boric acid (H3BO3) and calcium hydroxide (Ca(OH)2), then use these values to convert the mass of calcium hydroxide to moles and then to grams of boric acid.
The molar mass of potassium hydroxide (KOH) is 56.11 g/mol. Therefore, 1 mole of potassium hydroxide weighs 56.11 grams.
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).
No, because one mole of calcium hydroxide constitutes two equivalents of calcium hydroxide for neutralization, but one mole of phosphoric acid constitutes three equivalents of phosphoric acid for neutralization. Therefore, one mole of calcium hydroxide will neutralize only 2/3 of one mole of phosphoric acid.
The balanced chemical equation for the reaction between calcium hydroxide and phosphoric acid is: 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O Using the mole ratio from the balanced equation, we find that 1 mole of calcium hydroxide reacts with 2/3 mole of calcium phosphate. First, calculate the number of moles of calcium hydroxide: 21.5g / 74.093g/mol = 0.290 moles Then, use the mole ratio to find the moles of calcium phosphate that can be produced: 0.290 moles * (1 mole Ca3(PO4)2 / 3 moles Ca(OH)2) = 0.097 moles Lastly, convert moles of calcium phosphate to grams: 0.097 moles * 310.176g/mol = 30 grams of calcium phosphate could be recovered.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
It depends on what it is reacting with.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
One mole of calcium phosphide on reaction with excess water produces calcium hydroxide and phosphine gas. This reaction can be represented as Ca3P2 + 6H2O → 3Ca(OH)2 + 2PH3.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH