Be3(PO4)2--------------Beryllium phosphate
124,60 grams of Fe3(PO4)2 are equal to 0,35 moles.
Well, honey, the molar mass of strontium phosphate is approximately 182.24 grams per mole. It's like the weight of all the strontium and phosphate atoms in one mole of the compound, simple as that. So, if you need to calculate some stoichiometry or impress your chemistry teacher, now you know!
If you think to the molar mass this is 601,9237 g.
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.
To find the percent composition of phosphorus in Zn3(PO4)2, calculate the molar mass of the entire compound first. The molar mass of Zn3(PO4)2 is 386.06 g/mol. Then, determine the molar mass of phosphorus in the compound, which is 283.89 g/mol. Finally, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage. In this case, the percent composition of phosphorus in Zn3(PO4)2 is approximately 73.65%.
To find the percent composition of phosphorus in Zn3(PO4)2, calculate the molar mass of PO4 (phosphate) first. The molar mass of PO4 is 1 * P (phosphorus) + 4 * O (oxygen). Then, divide the molar mass of P by the molar mass of the entire Zn3(PO4)2 compound and multiply by 100 to get the percentage.
The molar mass of Ca3(PO4)2 is 310.18 g/mol. The molar mass of phosphorus is 30.97 g/mol. To find the percent composition of phosphorus, calculate the molar mass contribution of phosphorus in Ca3(PO4)2 and divide it by the total molar mass of the compound, then multiply by 100. (30.97 * 2) / 310.18 * 100 ≈ 20.01% Therefore, the percent composition of phosphorus in Ca3(PO4)2 is approximately 20.01%.
The percentage of phosphorus (P) in Mg3(PO4)2 is 28.7%. This is calculated by dividing the molar mass of P by the molar mass of the entire compound, then multiplying by 100 to get the percentage.
Fe3+ combines with PO43- ion to form FePO4 FePO4 is called ferric phosphate or iron(III) phosphate
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
Be3(PO4)2--------------Beryllium phosphate
The chemical formula of ferrous phosphate is Fe3(PO4)2.
The chemical formula of ferrous phosphate is Fe3(PO4)2.
124,60 grams of Fe3(PO4)2 are equal to 0,35 moles.
The molar mass of copper phosphate (Cu3(PO4)2) is approximately 380.58 g/mol.