The molar mass of Pb3(PO4)2 is 811,54 g.
14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.
The molar mass of vanadium II phosphate (V3(PO4)2) is calculated by adding the atomic masses of all the elements present in the compound. This includes the atomic masses of vanadium (V), phosphorus (P), and oxygen (O). The molar mass of vanadium II phosphate is approximately 285.85 g/mol.
To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
The chemical formula is (NH4)HPO4 (if you think to this phosphate). The molar mass is 132,07. The percentages of the elements are: - hydrogen: 6,86997 % - nitrogen: 21,21196 % - oxygen: 48,45843 % - phosphorous: 23,45964 %
The molar mass of copper phosphate (Cu3(PO4)2) is approximately 380.58 g/mol.
Well, honey, the molar mass of strontium phosphate is approximately 182.24 grams per mole. It's like the weight of all the strontium and phosphate atoms in one mole of the compound, simple as that. So, if you need to calculate some stoichiometry or impress your chemistry teacher, now you know!
To find the mass percent of hydrogen in ammonium phosphate NH4 3PO4, first calculate the total molar mass of the compound. Then, determine the molar mass contributed by hydrogen. Finally, divide the molar mass of hydrogen by the total molar mass of the compound and multiply by 100 to get the mass percent.
14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.
Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
The molar mass of vanadium II phosphate (V3(PO4)2) is calculated by adding the atomic masses of all the elements present in the compound. This includes the atomic masses of vanadium (V), phosphorus (P), and oxygen (O). The molar mass of vanadium II phosphate is approximately 285.85 g/mol.
To calculate the mass of phosphorus in 45.3 g of ammonium phosphate, you need to know the molar mass of ammonium phosphate (NH4)3PO4, which is approximately 149.09 g/mol. The mass percentage of phosphorus in ammonium phosphate is 30.97%. Therefore, the mass of phosphorus in 45.3 g of ammonium phosphate can be calculated as: 45.3 g x (30.97/100) = 14.02 g of phosphorus.
The equivalent weight of calcium phosphate is calculated by dividing the molar mass of calcium phosphate by the valency factor of the phosphate ion. Since calcium phosphate is a salt with the formula Ca₃(PO₄)₂, its molar mass is calculated by adding the molar masses of calcium and phosphorus (since there are three calcium ions and two phosphate ions in the formula). The valency factor of phosphate ion is 2 since it can donate or accept 2 electrons.
To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
To find the number of moles in 51 grams of lithium phosphate, you first need to determine its molar mass. The molar mass of lithium phosphate (Li3PO4) is 115.79 g/mol. To find the number of moles, divide the given mass by the molar mass: 51 g / 115.79 g/mol ≈ 0.44 moles of lithium phosphate.