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The molar mass of Pb3(PO4)2 is 811,54 g.

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What is the molar mass of copper phosphate?

The molar mass of copper phosphate (Cu3(PO4)2) is approximately 380.58 g/mol.


What is the molar mass of strontium phosphate?

Well, honey, the molar mass of strontium phosphate is approximately 182.24 grams per mole. It's like the weight of all the strontium and phosphate atoms in one mole of the compound, simple as that. So, if you need to calculate some stoichiometry or impress your chemistry teacher, now you know!


What is the mass percent of hydrogen in ammonium phosphate NH4 3PO4?

To find the mass percent of hydrogen in ammonium phosphate NH4 3PO4, first calculate the total molar mass of the compound. Then, determine the molar mass contributed by hydrogen. Finally, divide the molar mass of hydrogen by the total molar mass of the compound and multiply by 100 to get the mass percent.


What is the molar mass ammonium phosphate(NH4)3PO4?

14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.


What is the percent composition by mass of phosphorous in ammonium phosphate?

Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.


How many grams are in 0.658 mole of calcium phosphate?

To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.


What is the molar mass of vanadium II phosphate?

The molar mass of vanadium II phosphate (V3(PO4)2) is calculated by adding the atomic masses of all the elements present in the compound. This includes the atomic masses of vanadium (V), phosphorus (P), and oxygen (O). The molar mass of vanadium II phosphate is approximately 285.85 g/mol.


What mass of phosphorus is contained in 45.3 g of ammonium phosphate?

To calculate the mass of phosphorus in 45.3 g of ammonium phosphate, you need to know the molar mass of ammonium phosphate (NH4)3PO4, which is approximately 149.09 g/mol. The mass percentage of phosphorus in ammonium phosphate is 30.97%. Therefore, the mass of phosphorus in 45.3 g of ammonium phosphate can be calculated as: 45.3 g x (30.97/100) = 14.02 g of phosphorus.


How the equivalent weight of calcium phosphate be calculated?

The equivalent weight of calcium phosphate is calculated by dividing the molar mass of calcium phosphate by the valency factor of the phosphate ion. Since calcium phosphate is a salt with the formula Ca₃(PO₄)₂, its molar mass is calculated by adding the molar masses of calcium and phosphorus (since there are three calcium ions and two phosphate ions in the formula). The valency factor of phosphate ion is 2 since it can donate or accept 2 electrons.


Calculate the number of moles contained in 150g of calcium phosphate?

To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.


How many grams are contained in 5.5 moles of aluminum phosphate?

To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.


How many moles of lithium phosphate are in 51 grams of this substance?

To find the number of moles in 51 grams of lithium phosphate, you first need to determine its molar mass. The molar mass of lithium phosphate (Li3PO4) is 115.79 g/mol. To find the number of moles, divide the given mass by the molar mass: 51 g / 115.79 g/mol ≈ 0.44 moles of lithium phosphate.