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Well, honey, the molar mass of strontium phosphate is approximately 182.24 grams per mole. It's like the weight of all the strontium and phosphate atoms in one mole of the compound, simple as that. So, if you need to calculate some stoichiometry or impress your chemistry teacher, now you know!
What else can I help you with?
What is the mass percentage of strontium in strontium sulfide?
To calculate the mass percentage of strontium in strontium sulfide, you need to know the molar mass of strontium sulfide (SrS), which is 119.63 g/mol. The molar mass of strontium (Sr) is 87.62 g/mol. To find the mass percentage, you would divide the molar mass of strontium by the molar mass of strontium sulfide, and then multiply by 100. This would give you the mass percentage of strontium in strontium sulfide, which is approximately 73.2%.
What is the molar mass of strontium sulfide?
The molar mass of strontium sulfide (SrS) is 119.63 grams per mole. This value is calculated by adding the atomic masses of strontium (87.62 g/mol) and sulfur (32.07 g/mol) together.
What is the mass in grams of 1.15 mol of strontium sulfate?
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
How many grams are in 0.658 mole of calcium phosphate?
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
175.24 g of strontium equal how many moles?
To calculate the number of moles in 175.24 g of strontium, divide the given mass by the molar mass of strontium (87.62 g/mol). This gives you 175.24 g / 87.62 g/mol = 2 moles of strontium.
What is the mass percentage of strontium in strontium sulfide?
To calculate the mass percentage of strontium in strontium sulfide, you need to know the molar mass of strontium sulfide (SrS), which is 119.63 g/mol. The molar mass of strontium (Sr) is 87.62 g/mol. To find the mass percentage, you would divide the molar mass of strontium by the molar mass of strontium sulfide, and then multiply by 100. This would give you the mass percentage of strontium in strontium sulfide, which is approximately 73.2%.
What is the molar mass of copper phosphate?
The molar mass of copper phosphate (Cu3(PO4)2) is approximately 380.58 g/mol.
What is the molar mass of lead(III) phosphate Pb3(PO4)2.?
The molar mass of lead(III) phosphate (Pb3(PO4)2) can be calculated by adding the molar mass of lead (Pb) and the molar mass of phosphate (PO4) in the compound. The molar mass of Pb is 207.2 g/mol and the molar mass of PO4 is 94.97 g/mol. Therefore, the molar mass of Pb3(PO4)2 is 3(207.2) + 2(94.97) = 611.54 g/mol.
What is the molar mass of strontium sulfide?
The molar mass of strontium sulfide (SrS) is 119.63 grams per mole. This value is calculated by adding the atomic masses of strontium (87.62 g/mol) and sulfur (32.07 g/mol) together.
What is the mass in grams of 1.15 mol of strontium sulfate?
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
What is the mass percent of hydrogen in ammonium phosphate NH4 3PO4?
To find the mass percent of hydrogen in ammonium phosphate NH4 3PO4, first calculate the total molar mass of the compound. Then, determine the molar mass contributed by hydrogen. Finally, divide the molar mass of hydrogen by the total molar mass of the compound and multiply by 100 to get the mass percent.
Name of sr(io)4?
Strontium Periodate and it has a molar mass of 469.4241
What is the molar mass ammonium phosphate(NH4)3PO4?
14x3+12+31+16x4=149 The molar mass of NH43PO4 is 149.
What is the percent composition by mass of phosphorous in ammonium phosphate?
Ammonium phosphate ((NH4)3PO4) contains one phosphorus atom in the formula. To calculate the percent composition by mass of phosphorus, you need to find the molar mass of phosphorus and the molar mass of the entire compound. Then, divide the molar mass of phosphorus by the molar mass of the compound and multiply by 100 to get the percentage.
How many grams are in 0.658 mole of calcium phosphate?
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
What is the chemical name of Sr3 PO4 2?
Sr3(PO4)2 is stronium phosphate. Strontium OrthoPhosphate.
What is the molar mass of vanadium II phosphate?
The molar mass of vanadium II phosphate (V3(PO4)2) is calculated by adding the atomic masses of all the elements present in the compound. This includes the atomic masses of vanadium (V), phosphorus (P), and oxygen (O). The molar mass of vanadium II phosphate is approximately 285.85 g/mol.
