The volume of one mole of oxygen can be estimated by the ideal gas law. In this case, you will use V = nRT/P, where n is the moles of gas, R is the ideal gas constant, T is the temperature in kelvin, P is the system pressure.
The molar mass of any gas in liters is 22.4
For example
The molar mass of O2 and O are both 22.4 since gas is compressible.
The amount of oxygen is 0,067 moles.
At standard temperature and pressure, one mole of gas takes up 22.4 liters. So the amount of gas necessary to occupy 2 liters is:2 L ÷ 22.4 mole/L = 0.08929 molesOne mole of oxygen gas (O2) weighs 32 grams per mole, so:0.08929 moles * 32 g/mole = 2.857 grams of O2The density of liquid oxygen is 1.141 g/cm³, and so the volume is:2.857 grams ÷ 1.141 g/cm3 = 2.50 cm3 = 2.50 mLIn other words, oxygen expands by a factor of 800 going from liquid to gas!See the Related Questions link to the left for more information on solving Ideal Gas Law problems of this type.
One mole takes 22.4l at STP.So 3.6l has 0.16mol
Since each mole of carbon dioxide molecules contains two moles of oxygen atoms, as indicated by the formula CO2 for carbon dioxide, half a mole of carbon dioxide will have one mole of oxygen atoms.
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
The volume is 64,8 L.
1 mole = 22.414 liters So, 3.5 mole = 78.45 liters
22.4litres
1 mole CaCO3 (3 mole O/1 mole CaCO3) = 3 moles oxygen
At STP, one mole of any gas occupies 22.4 liters. This is called molar volume. 113.97 liters ÷ (22.4 L/mol) = 5.09 moles Then convert moles to molecules (1 mole = 6.02 × 1023 molecules) 5.09 moles × (6.02 × 1023 molecules/mol) = 3.06 × 1024 molecules
How many litres of oxygen is 28 % using a face mask?
The amount of oxygen is 0,067 moles.
1 mole (or 4 g of He) occupies 22.414 liters. So, 2.3 mole occupies 2.3 x 22.414 liters = 51.5522 liters
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
There is 1 Avagadro number - so, 6.022 x 1023 molecules in 1 mole of oxygen.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.