Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
It is 1 atom of S to 2 of O.
Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.
The molecular mass of sulfur dioxide is 64,07.
Assuming the reaction is S + O2 --> SO2, this equation is balanced as written, with everything in a 1:1 molar ratio. So, 67.1 moles of product would require 67.1 moles of O2 reactant.
1:2, does this need explaining???? 1-O2 for every 2-SO3 thus 1:2
Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.
Assuming the equation for the reaction is S + O2 --> SO2, you first determine how many moles are in 12.6L of SO2: 12.6/22.4 = 0.56mol (22.4L = 1mol of any gas at STP.) The equation's molar ratio tells us that 0.56mol SO2 means 0.56mol S, because everything's in a 1:1 ratio. Now, consider sulfur's atomic mass of 32.1g/mol. 32.1x0.56 = approx. 18g sulfur. Now, if your sulfur is the S8 allotrope, you'll have to re-calculate for that.
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
It is 1 atom of S to 2 of O.
Assuming that the questioner meant "SO2" instead of the nonexistent "So2": The gram molar mass of SO2 is 64.06. Therefore, 2.56 g contains 2.56/64.06 or 3.97 X 10-2 mole, to the justified number of significant digits.
S8 + 8o2 --> 8so2
In what compound??
The molar mass of sodium chloride is 58,44 g. The molar mass of sodium bicarbonate is 84,007 g. The ratio is 1,437.
No, the molar ratio is not necessarily the same as the volume ratio for non-gaseous reactions. The molar ratio refers to the ratio of the number of moles of reactants or products involved in a chemical reaction. It is determined by the balanced chemical equation. On the other hand, the volume ratio refers to the ratio of the volumes of reactants or products in a reaction. In some cases, the volume ratio may be equal to the molar ratio, especially for ideal gases at the same temperature and pressure. This is known as the ideal gas law and is represented by Avogadro's principle. However, for non-gaseous reactions, the volume ratio may not necessarily be equal to the molar ratio. This is because the volume of a substance is influenced by factors such as density, state (solid, liquid, or gas), and the presence of solvents or other compounds. Therefore, it is important to use the molar ratio when determining stoichiometry and reaction quantities, rather than relying solely on volume ratios.