Assuming the equation for the reaction is S + O2 --> SO2, you first determine how many moles are in 12.6L of SO2: 12.6/22.4 = 0.56mol (22.4L = 1mol of any gas at STP.) The equation's molar ratio tells us that 0.56mol SO2 means 0.56mol S, because everything's in a 1:1 ratio. Now, consider sulfur's Atomic Mass of 32.1g/mol. 32.1x0.56 = approx. 18g sulfur. Now, if your sulfur is the S8 allotrope, you'll have to re-calculate for that.
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
1.434 g/cm3
The mass is 11 g.
The molecular mass of a sulfur molecule is 32 g.
Oxygen is 49.95% of the mass of SO2. The molecular weight is 48.06 g/mol and sulfur's molecular weight is 32.06 g/mol, so oxgyen must make up the other half of the compounds molecular weight.
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A sulfur dioxide has one sulfur atom and two oxygen atoms. Therefore, considering a mole of sulfur dioxide (64g); there is 32g of sulfur and 32g of oxygen. Hence the mass percent of oxygen is 50%.
The molecular mass of sulfur dioxide is 64,07.
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
The maximal mass is 30 moles sulfur dioxide.
1.434 g/cm3
The mass is 11 g.
The relative atomic mass of sulfur is 32. And for oxygen, it is 16. Therefore the molecular weight of sulfur dioxide is 64 g/mol.
CO2 diffuses faster because it has a lower molecular mass.
3.82g of SO2 equals 0,06 moles.