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Oxygen is 49.95% of the mass of SO2. The molecular weight is 48.06 g/mol and sulfur's molecular weight is 32.06 g/mol, so oxgyen must make up the other half of the compounds molecular weight.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoSulfur dioxide contain 49,95 %.
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What is the percent composition by mass of SO2?
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How to prepare acetophenone from phenol in not more than 2 steps?
Ph-OH + CF3SO2-O-SO2-CF3 -> Ph-O-SO2-CF3 + (CH2=CH)-O-Bu + Ph2P(CH2)3PPh2 + Pd(OAC)2 + DMF, then HCl-> Ph-(C=O)-CH3
What is the oxidation of SO2?
S = +4 oxidation state O = -2 oxidation state
What is the mass percentage of each element in the compound sodium hydroxide?
Molar mass Na: 23 g/mol O : 16 g/mol H : 1 g/mol Total NaOH: 40 g/mol Mass percentage %Na: 23/40 = 57.5% %O : 16/40 = 40% %H : 1 /40 = 2.5%
Is SO2 a single atom?
No, its a molecule composed of an atom of sulfur (S) and 2 atoms of oxygen (O)
What is the mass percent of oxygen (O) in SO2?
(16.0g + 16.0g)/(32.1g + 16.0g + 16.0g) x 100 %
What is the mass percent of oxygen in SO2?
The mass percent of oxygen in SO2 is 50 %.
What does so2 look like?
O=s->o
What is the mass percent in oxygen SO2?
I assume you mean mass of oxygen % in SO2. This is calculated by finding the molecular weight of S and O (32 and 16 respectively) As there are 2 oxygens, 16 is multiplied by 2, = 32. put 32 over the total, = 32/64. Which equals 50%
What is the empirical mass of SO2 Answer using four significant figures.?
The answer will depend on the unspecified quantity of SO2.
What is the mass of 0.75 mole of so2?
The molecular mass of SO2 = 32 + 2(16) = 64. Then 64 g * 0.75 = 48 g.
How many moles are there in 3.82g of SO2?
3.82g of SO2 equals 0,06 moles.
What is the molar mass of so2?
The molecular mass of sulfur dioxide is 64,07.
How many moles are present in 128 grams of sulphur dioxide?
Divide mass of 128 g SO2 by its molar mass of 64.066 g.mol−1 SO2 and you get the number of moles: 1.9979 = 2.00 mole SO2
Why does co2 diffuse faster than so2?
CO2 has lesser molecular mass than SO2 also Co2 is less reactive than SO2:)
How many moles in 37.4g of SO2?
The formula mass of the compound sulfur dioxide, SO2 is 32.1 + 2(16.0) = 64.1Amount of SO2 = mass of pure sample/molar mass = 37.4/64.1 = 0.583mol There are 0.583 moles of sulfur dioxide in a 37.4g pure sample.
What is the percent composition of sulfur in SO2?
32.1g __________________ X100% (32.1g + 16.0g + 16.0g)
