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The molarity is 0,268.

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Q: What is the molarity of 10.0 g of KCl in 0.500 L of solution?
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The molarity of a solution of 5.0 g of KCl in 100 mL of solution is?

0.67 M


What is the molarity of a solution that contains .202 mol KCI in 7.98 L of solution?

Molarity = moles of solute/Liters of solution Molarity = 0.202 moles KCl/7.98 Liters = 0.253 M KCl solution ================


What is the molarity of a solution that contains 0.202 moles KCl in 7.98 liters of solution?

The molarity is 0,025.


What is the molarity of a solution made by dissolving 4.88 g of KCl in 423 mL of solution?

Need mole KCl first. 4.88 grams KCl (1 mole KCl/74.55 grams) = 0.06546 moles KCl =======================now, Molarity = moles of solute/Liters of solution ( 423 ml = 0.423 Liters ) Molarity = 0.06546 moles KCl/0.423 Liters = 0.155 M KCl ------------------


What is the molarity of a solution that contains 0.202 mol KCl in 7.98 L solution?

.0253M


What is the molarity of a solution that contains 345 moles KCL in 8.6 L solution?

.487 Kl


What is the molarity of a solution that contains 0.202 mol KCl in 7.98 L of solution?

0.202/7.98 = 0.0253 molar


What is the molarity of a solution where 4.00 moles of Potassium Chloride is dissolved in 3.00 L of solution?

The molarity of a solution given by the number of moles divided by the volume it contains. Hence, the molarity of KCl is 4.00/3.00 = 1.33 mol/L.


What is the molarity of a solution that has mol of kcl in 0.800 kg in water?

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What is the molarity of a solution prepared when 75.0 ml of a 4.00 m kcl solution is diluted to a volume of 0.500 l?

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How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?

Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed


How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?

M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution