15g in 100L is 0.15g/ litre. The molecular weight of NaOH is 40g/mol. 0.15/40 is .00375 molar.
100 g of solution containing 50 g of NaOH.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
It's very easy as the molarity and normality of NaOH is the same. so all you need to do is to decide how much (volume) of that you need. the molar mass of NaOH is 40.5 gr, so 5 molar (normal) solution needs times five of that in 1 litre. 5*40.5=202.5 dissolve it in 1 liter water (be careful as the dissolving process is highly exothermic) Now you have 1 litre of 5 normality NaOH.
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
40 g NaOH in 1 liter is 1 molar. So 400 mg = 0.4 g in 100 ml = 4 g per liter and thus 0.1 molar.
100 g of solution containing 50 g of NaOH.
I think it'd be pH 7. Same amount of both, providing they are the same molarity!
Molarity is moles per litre. So here, you have to divide by 353ml, x 1000 (to get it per litre). .73/353*100 is 2.07 molar.
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
It's very easy as the molarity and normality of NaOH is the same. so all you need to do is to decide how much (volume) of that you need. the molar mass of NaOH is 40.5 gr, so 5 molar (normal) solution needs times five of that in 1 litre. 5*40.5=202.5 dissolve it in 1 liter water (be careful as the dissolving process is highly exothermic) Now you have 1 litre of 5 normality NaOH.
0.67 M
Dissolve slowly 50 g NaOH in 100 mL water; advertisement: sodium hydroxide solution is dangerous !
40 g NaOH in 1 liter is 1 molar. So 400 mg = 0.4 g in 100 ml = 4 g per liter and thus 0.1 molar.
endpoint
A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution