Top Answer

Molarity = moles of solute/Liters of solution

Find moles NaCl

9 grams NaCl (1 mole NaCl/58.44 grams)

= 0.154 moles NaCl

Molarity = 0.154 moles NaCl/1 Liter

= 0.2 M sodium chloride

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0Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.

There would be 117g of NaCl in 1000 ml or 1 liter. The MWt of NaCl is 58.5 so 117/58.5 is 2.00 - so the molarity is 2.00 moles per liter of NaCl

Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------

One mole of NaOH is 40g. So 40g dissolved in 1 litre will give a 1M solution.

Molarity = moles of solute/Liters of solution Molarity = 5 moles solute/4.5 Liters of solution = 1 M solution ==========

# of moles of solute Molarity = -------------------------- 1 Liter of solution

1 because Na ions have a +1 charge while Cl ions have a -1 charge.

Molarity:1.0 mol (NaOH) /L(solution) = 1.0 M NaOHThe conversions of molality, b, to and from the molarity , c,for one-solute solutions are:c = ρ.b / [1 + b.M]andb = c / [ρ -c.M]where ρ is the mass density of the solution, b is the molality, and M is the molar mass of the solute.

Molarity=no. of moles of solute/vol of solution in(L) molarity=0.4/9.79=0.04086 mol L-1=0.04086 M.

1. An homogeneous solution of sodium chloride in water is obtained. 2. Sodium chloride is dissociated in Na+ and Cl-.

+1 for Na and -1 for Cl.

This is called an ionic bondExample:Na --> Na+ + 1 e-Cl + 1 e- --> Cl-Na+ + Cl- --> Na+Cl-

molarity is the number of moles dissolved per volume of a solution in dm cube molarity=mass of solute in gram __________________ 1 * _________________ molecular mass of solute volume of solution in dm cube OR molarity=no.of moles ________________ volume of solution in dm cube

As a thought experiment - suppose you mixed one liter of 1M HCl with 1 liter of 1M NaOH. The resulting solution (neglecting any density changes associated with mixing) would contain 2 liters with 1 mole of Cl- and 1 mole of Na+ with the balance being water (the H+ from the HCl and the OH- from the NaOH would just become part of the water). This would give you a 0.5 M solution of NaCl.

1620 ml = 1.62 Liters Molarity = moles of solute/Liters of solution Molarity = 2 moles NaOH/1.62 Liters = 1 M NaOH solution ===============

Molarity is number of moles in solute. So molarity of this is 0.5mol-1.

Cl is +1; O is -2; Na is +1

Molarity or molar concentration is a unit of concentration, symbolized by "M". It is the ratio of the number of moles of solute and the volume of solution (in liters).Molarity = Moles of solute ÷ Liters of solution = moles/liter = Mmolarity is define as the number of mole of a solute in 1 liter of solution.

You need to get it per litre. 250x4 will give you 1 litre, so 0.325x4 will give you your molarity. This gives a molarity of 1.3 (molar).

Molarity is defined as moles/liters. So the concentration of your solution (your answer) is 1 M. You have a one molar solution (mol/L).

1000 ppm = 1 part per 1000. Sodium is 40 atomic weight and to be 1 molar there would have to be 40 parts per thousand. So the molarity is 1/40 = 0.025 M

Molarity gives the no. of moles of solute per litre of the solutionFor instance, 1 M HCl means 1 mole of pure HCl in 1 L of water

The molarity is 6 mol/l.

it is expressed in molarity. if a mole of solute is dissolved in 1 liter of solution, the solution is said to be have concentration of 1M (M=molarity)

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