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What is the molarity of a HCI solution that contains 10.0 g of HCI in 250 mL of solution?
Wiki User
∙ 12y ago
First find the moles of HCl
mol(HCl) = 10g / (35.5+1) = 0.2740 moles
Hence molarity(M) = 0.2740/ 0.2dm^3(Litres)
Hence molarity(M) = 0.2740/ 0.25 = 1.0958 mol dm^-3 = 1.0958 M
As an approximation it would be 1.1 M
lenpollock
Wiki User
∙ 12y agoGet moles HCl first.
10.0 grams HCl (1 mole HCl/36.458 grams)
= 0.2743 moles HCl
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you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
675
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
0.0125
How many moles of CaCl2 are in 250 ml of CaCl2 solution?
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
How much 2M Nacl solution would you need to make 250ml of 0.15M Nacl solution?
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
675
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
0.0125
What is the molarity of a solution that contains 0.65 moles of NaNO3 in 250 mL of solution?
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
How many moles of CaCl2 are in 250 ml of CaCl2 solution?
It depends on the concentration of the solution. If you know the concentration(molarity) then use the equation. moles = [conc] x vol(mL) / 1000 NB The '1000' isusedto convert the concentration units of moles per litre (molL^-1) to mL.
A solution contains 30 g of calcium chloride in 250 g of water express the mass percent?
The solution has a total mass of 30 + 250 = 380 g. The mass percent of calcium chloride in this solution is 100(30/380) = 7.9 %, to the justified number of significant digits.
When 100. ml of when 100. ml of 0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i0.125 m hcl is diluted to 250. ml the resulting molarity of the hcl solution i?
Molarity = mole of solute/liter of solution. The unit for molarity is mol/L, and is abbreviated M or molar. Use the equation below, where M1 and M2 are molarity, and V1 and V2 are volume. The volumes given in mL must be converted to liters (L) by multiplying mL by 1 L/1000 mL. For example: 420 mL x 1 L/1000 mL = 0.420 L (The decimal is moved to the left three spaces.)M1V1 = M2V2, where M1=0.125 mol/L, V1=100. mL = 0.100. L, V2 = 250. mL = 0.250. L., M2 is unknown.Rearrange the equation to isolate M2. Plug in the known data and solve.M2 = (M1V1)/(V2)M2 = (0.125 mol/L x 0.100. L)/(0.250. L) = 0.05 mol/L = 0.050 M HCl
750 ml of 20M HCl is mixed with 250 ml of 60M HCl What is the new molarity?
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
How much 2M Nacl solution would you need to make 250ml of 0.15M Nacl solution?
By the definition of molarity, which is mass of solute in moles divided by solution volume in liters, 250 ml of 0.15 M NaCl* solution requires (250/1000)(0.15) or 0.0375 moles of NaCl. Each liter of 2M NaCl solution contains 2 moles of NaCl. Therefore, an amount of 0.0375 moles of NaCl is contained in (0.0375/2) liters, or about 18.75 ml of the 2M NaCl, and if this volume of the more concentrated solution is diluted to a total volume of 250 ml, a 0.15 M solution will be obtained. _________________ *Note correct capitalization of the formula.
What is the molarity of a solution containing .325 moles of solute in 250 ml of solution?
Given the eqaution c=n/v, where:c = concentrationn = number of molesv = volumeso, n=cv, that is: n = .25 X .4= 0.1 mol
What is the osmolarity of a solution containing 100 grams of KCl in 250 ml of water?
moles of KCl = 100 g x 1 mole/74.5 g = 1.34 molesvolume = 250 ml = 0.25 L molarity = moles/liter = 1.34 moles/0.25 L = 5.37 M Since KCl dissociates completely into K+ and Cl-, you have 5.37 M of each = total of 10.74 osmolar
Which value of x is a solution of the inequality 25x -100 250?
13
What is the volume of 250 M KCl solution if it contains 2.0 mole of KCl?
250 M means contains 250 moles per liter, which is probably impossible 1) . However, taking the question as stated, the answer is (2.0 mole)/(250 moles/liter) = 0.0080 liter or 8.0 milliliters, to the justified number of significant digits.1) Commented: It is impossible!The solution in this question is really impossible in every way:The highest solubility of KCl in boiling water that is: 567 g/L (100 °C), the molar mass being 74.551 g/mol, this is 7.6 mol/L ( = 7.6 M)Even one Litre pure (molten) KCl can not contain 250 moles! The density if pure KCl is (less than) 1.984 g/cm3 , being equal to 0.027 mol/mL =27 mol/L with NO solvent added. ( = 27 M)
