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What is the volume of 250 M KCl solution if it contains 2.0 mole of KCl?
Wiki User
∙ 13y ago
250 M means contains 250 moles per liter, which is probably impossible 1) . However, taking the question as stated, the answer is (2.0 mole)/(250 moles/liter) = 0.0080 liter or 8.0 milliliters, to the justified number of significant digits.
1) Commented: It is impossible!
The solution in this question is really impossible in every way:
- The highest solubility of KCl in boiling water that is: 567 g/L (100 °C), the molar mass being 74.551 g/mol, this is 7.6 mol/L ( = 7.6 M)
- Even one Litre pure (molten) KCl can not contain 250 moles!
The density if pure KCl is (less than) 1.984 g/cm3 , being equal to 0.027 mol/mL =
27 mol/L with NO solvent added. ( = 27 M)
Wiki User
∙ 13y ago
Wiki User
∙ 15y ago%(v/v) = [(volume of solute)/(volume of solution)] x 100% 2% =[(volume of solute)/250 mL] x 100% 2%/100% = volume of solute/250 mL 0.02 x 250 mL = volume of solute 5 mL = volume of solute
Wiki User
∙ 12y agoMolarity (M) = mols / L
0.4 = mol / 0.250L
mol = (0.4) (0.250)
mol = 0.1
Wiki User
∙ 7y agoThe answer is 0,625 moles.
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