2 moles in 2 liters means 1 mole in 1 liter - so it its molarity is 1.
find mole: glucose = C6H12O6 = molar mass is 180g... 36g glucose / 180g glucose = .2 mole
molarity = mol/L = .2 mol / 2 L = .1M
The molarity is 0,75 mol/L.
The molarity is 0,75 mol/L.
15g in 100L is 0.15g/ litre. The molecular weight of NaOH is 40g/mol. 0.15/40 is .00375 molar.
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
2.5 0.05 L (50 mL) * 15 Mol/L= 300 Mol/L * X litres (0.05 L * 15 Mol/L) / 300 Mol/L = 0.0025 L or 2.5 mL
Molarity = moles of solute/liters of solution ( 15ml = 0.015 liters ) 2.9 M NaOH = moles NaOH/0.015 liters = 0.0435 moles of NaOH
For a concentration of 0,6 g sugar/1000ml: 15 ml for 150 mL.
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
15g in 100L is 0.15g/ litre. The molecular weight of NaOH is 40g/mol. 0.15/40 is .00375 molar.
you simply divide the gram amount of sugar by the gram amount of water, and multiply by 100. So the mass percent is (2.45/200)x100=1.225%
.15
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
2.89
molarity = number of moles of solute / volume of solution number of moles of solute = molarity x volume of solution number of moles of solute = 12 (mole/L) x 15/1000 (L) number of moles of solute = 0.18 mole
Molarity of a solution is the number of moles of the solute divided by the volume of the solution (in liters). If 750 ml of 20M HCl is mixed with 250 ml of 60M HCl, we first find the total number of moles of HCl in our new solution. Using that same formula, M=moles/V, we cansee that moles=MV. In the first solution we have (20M)(0.750L) = 15 moles. In the second, (60M)(0.250L) = 15 moles, so we have a total of 30 moles in our new solution, which also has a volume of 750mL + 250mL = 1L. The molarity of the new solution is 30 moles/1L = 30M
The molarity is 6.
2.5 0.05 L (50 mL) * 15 Mol/L= 300 Mol/L * X litres (0.05 L * 15 Mol/L) / 300 Mol/L = 0.0025 L or 2.5 mL
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
Firstly place 100 to 150 mg of aspirin into a 125 ml conical flask. Next proceed to mix in 15 ml of 95% ethanol solution and add 2 drops of phenolphthalein indicator. Then use the titration method to mix this solution against a standard solution of sodium hydroxide from a burette. Using the value obtained from the titration calculate the molarity of the aspirin. Then calculate the ratio of the observed molarity of aspirin with its theoretical molarity and finally multiply this ratio with 100 to obtain the percentage purity of the aspirin sample.