.15
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
0.375
18%
14.625
You take 1.00 mole NaCl, this is 58.45 grams dry substance NaCl, and add (while dissolving) up to 1.00 L water (so you'll need about 0.95 L -LESS than 1.00 L- of water).
You need the balanced symbol equation for the reaction. The numbers in front of the formulae show the mole ratios. For example, in the thermal decomposition of calcium carbonate: CaCO3 --> CaO + CO2 The equation is balanced. The mole ratio between CaCO3 and CO2 is 1:1 because there is 1 mole of CaCO3 for every mole of CO2
0,98
First You have to express the 200 g NaCl as moles of NaCl. The molar mass of NaCl is 58.5 g/mole. Consequently you need 200/58.5 g/(g/mole) = 3.42 moles of NaCl.Having a 2.10 M NaCl solution You need 3.42/2.10 mole/(mole/l) = 1.63 l of the given solution.
58 grams of NaCl in cylinder measure water to 100ml
Molarity = moles of solute/Liters of solutionGet moles NaCl.58.44 grams NaCl (1 mole NaCl/58.44 grams)= 1 mole NaCl------------------Molarity = 1 mole NaCl/1 liter= 1 M NaCl========
0.375
number of moles is mass divided by molecular mass. the molecular mass of NaCl is 58.44g/mol. therefore you need 58.44g to make one mole
The mole fraction of HCl in 20 percent aqueous solution is 0.21.
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
1.5g NaCl x (1 mole / 58.5 g NaCl) x (1000 ml / 0.42 mole) = 61.05 ml
18%
0.10