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What is the molarity of a solution when 25.0 g of aluminum sulfite is dissolved in distilled water and made up to 175.0 ml of solution?
Wiki User
∙ 7y ago
Al2(SO3)3 has r.f.m.= (2x27 + 3x32 + 9x16) = 294 Thus 25 g is 25/294 = 0.085 moles of aluminium sulfite.
We have 0.085 moles in 175 ml of solution, which would be 0.085 x 1000/175 moles in a litre
= 0.486 M
Wiki User
∙ 7y ago
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