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10kg of water contains 10l of water. So morality is 0.2mildm-3.
By dissolving 2 moles of the compound in 1 L of water
By dissolving 2 moles of the compound in 1 L of water
Molality is defined as moles of solute per kg of solvent. Thus, 3 moles/6 kg = 0.5 moles/kg = 0.5 m
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
0.33 mol/kg
The molarity is 0,33.
The molarity is 0,2.
By dissolving 2 moles of the compound in 1 L of water
Molality =moles of solute/kilograms of solvent Moles of solute =2
10kg of water contains 10l of water. So morality is 0.2mildm-3.
0.33 mol/kg (apex)
By dissolving 2 moles of the compound in 1 L of water
By dissolving 2 moles of the compound in 1 L of water
0.2
what is the molarity of a solution prepared by dissolving 36.0g of NaOH in enough water to make 1.50 liter of solution?
Molality is expressed as moles solute/kg solvent. Moles of solute = 2. Kg solvent = 6.Molality = 2 moles/6 kg = 0.33 molal