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What is the molatiy of a solution that has 6 mol of CaCl2 in 3 kg of water?
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What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the gram fromula mass of CaCl2?
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
How do you make a 1 mol manganese dioxide solution?
Manganese dioxide is insoluble in water.
What is the molarity of a solution of 3 moles mol of FeBr3 in L water?
3mol/0.5L
What is the molality of a solution that has 6 mol of CaCl2 in 3km of water?
2 m is the molarity of a solution that has 6 mol of CaCl2 in 3 km of water.
What is the molality of a solution that has 6 mol of cacl2 in 3kg of water?
2m
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
What is the molality of a solution that has 6 mol of CaCl2 in 3 kg of water?
2 m
How would you make 450 mL of a 25 M calcium chloride solution?
You'll need: 0.450 (L) * 25 (mol/L) = 11.25 mol CaCl2 and add water to it up to 450 mL.To be weighted:11.25 (mol CaCl2) * [40.08 + 2*35.45](g/mol CaCl2) = 1491.736 g = 1500 g =1.5 kg CaCl2 (CaCl2 as dry substance!, not hydrated)
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
What is the freezing point of a solution that contains 2.0 mol of CaCl2 in 800.0 g of water Kf for water equals 1.86Cm?
2.0 mol of CaCl2 releases 2.0 mol of Ca+2 ions & 4.0 mol of Cl- ions = 6 moles of ions find molality: 6 moles / 0.800 kg water = 7.5 molal solution dT = kf (molality) dT = 1.86 C (7.5m) dT = 14 Celsius drop in freezing temp the new freezing point is - 14 C
Determine the number of moles of Cl in 1.9 mol CaCl2?
Ca-1(40.08)g=40.8g/mol of Ca Cl-2(35.45)g=70.9g/mol of Cl2 40.08g+70.9g=110.98g/mol CaCl2 110.98g CaCl2/1mol * 1.9mol =210.86 g of CaCl2
What is the mass of 0.89 mol of CaCl2?
0.89 moles of CaCl2 is equal to 98.8g.
A solution containing 14 grams of AgNo3 is added to a solution containing 4.83 g of CaCl2. Find the mass of the precipitate produced.?
Ok, lets begin by writing out the reaction : 2AgNO3 +CaCl2 --> 2AgCl(s) + Ca(NO3)2 Precipitate = AgCl Now find the mol of compound in each solution: 14g AgNO3 x (mol/170g) = .082mol 4.83g CaCl2 x (mol/111g) = .044mol Determine limiting reactant: Notice in reaction that 2 CaCl2 molecules react with 1 AgNO3. Because 2(.044mol) > 1(.082mol), AgNO3 is your limiting reactant. Now that you know this you can find the mass of the precipitate .082molAgNO3x (2molAgCl/2molAgNO3)x(143.3g/molAgCl) = 11.75g b) Assuming all the AgNO3 is exhausted, there will be 2(.044)-(.082) = .006mol CaCl2 left .006mol x (111g/mol) = 0.67g CaCl2
What is the gram fromula mass of CaCl2?
The formula mass of (anhydrous) CaCl2 is: 110,99 g/mol;as dihydrate CaCl2.2H2O it is: 147,01 g/mol
What is the concentration of nitric acid in moles per liter in a sample which has density 1.41gm per ml and the mass percent of nitric acid is 69 percent?
Molarity is probably the most commonly used unit of concentration. It is the number of moles of solute per liter of solution (not necessarily the same as the volume of solvent!). Example: What is the molarity of a solution made when water is added to 11 g CaCl2 to make 100 mL of solution? Solution: 11 g CaCl2 / (110 g CaCl2 / mol CaCl2) = 0.10 mol CaCl2 100 mL x 1 L / 1000 mL = 0.10 L molarity = 0.10 mol / 0.10 L molarity = 1.0 M http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm http://www.tpub.com/content/MIL-SPEC/MIL-P/MIL-P-71158/MIL-P-7115800013.htm http://www.tpub.com/content/armymedical/md0837/md08370139.htm
