2:1
You need to add more water so that the salt to water ratio is less Mehwesh T
salt and water
Oxalic acid forms an oxalate salt when reacted with two equivalents of base - the name of the salt depends on the composition of the base. For example, if one mole of oxalic acid reacts with two moles of sodium hydroxide (NaOH), then one mole of sodium oxalate and two moles of water are formed. (Sodium oxalate is Na2C2O4.) If one mole of oxalic acid reacted with two moles of ammonia (NH3), then one mole of ammonium oxalate ((NH4)2C2O4) and two moles of water are formed.
A 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.
No, because salt usually stays in a solid form. if you tried to evaporate saltwater, dry salt would be left behind. That's what people used to do with ocean water to get table salt. Hope I helped!
An anhydrous sals hasn't water.
The ratio of salt water to fresh water on the Earth is approximately 40 to 1. The oceans are comprised of salt water.
You think probable to concentration of salt in water.
Adding one mole of salt raises the boiling point of the water more than adding one mole of sugar to the water
This is because the mole fraction of water in salt solution is lower than the mole fraction of water in pure water and salt is not volatile - has no appreciable vapour presure. This is an instance of Raoult's Law in action. In very simple terms the number of water molecules at the surface of the water is less when there is salt present thus lowering its vapour presure.
The density of a salt water solution compared against the densities of "pure" water and salt provides an approximate value of the ratio of water to salt in the mixture.
sugar is a covalent compound where as salt is an ionic compound,so salt while dissolving in the water splits.This is mainly dependent of the 'total dissolved partical' concentration (mol/L):Sugar (C6H12O6): 1 mole particles per 180 g (for 1 mole sugar)Salt (NaCl) 2 mole particles per 58.5 g (for 1 mole salt) = 6 mole particles per about 180In water the freezing point will be lowered by 1.86oC per mole particles dissolved: So 180 g/L sugar: freeze at -1.86oCand 175.5 g/L salt freeze at -(6*1.86) = -11.2oCor 29.2 g/L salt will freeze at the same as 180 g suger: -1.86oC
sollution with a 1 to 1 ratio of salt to water
You need to add more water so that the salt to water ratio is less Mehwesh T
salt and water
Safe ratio would be 75 mil of Acid to 1 Litre of Water
yes, if enough fresh water was added it could dissolve the salt. evaporation would not work though. the salt would stay and the water turns into vapor in the air leaving a higher salt : air ratio. ++++ The first sentence is wrong. The salt is ALREADY dissolved! The water turns into vapour at it surface and leaves the salt behind. There is no "salt:air ratio".