An anhydrous sals hasn't water.
The mole ratio is 1/5.
1.2
Safe ratio would be 75 mil of Acid to 1 Litre of Water
Working to find the xH2O in salt Taking that quantities of salt solution and acid are expressed in thousandths of a litre, it follows that mol of acid used = 0.0488 x 0.01 = 0.000488 From equation for reaction between acid and salt, Na2CO3 + 2HCl -----> 2NaCl + CO2 + H2O 2 mol of acid reacted with one mole of salt so, mol of salt used = 0.000488/2 = 0.000244 Mol of salt in 1l = 0.000244 x 1000/2.5 = 0.0976 Mass of salt in 1l = 0.0976 x 106g = 10.35g But mass of hydrated salt used was 27.82g So, mass of water in salt = 27.82 - 10.35g = 17.47g Mass ratio of salt to water is 10.35:17.47 Mole ratio of salt to water is 10.35/106:17.47/18 = 0.0976:0.971 or 1:10 dividing by smallest component of ratio therefore moles of water in hydrated salt = 10 Hence formula of salt is Na2CO3.10H2O
it is usually around the measurement of 6.0~ 7.4. However, it really depends on the ratio of the water and the epsom salt. it also depends on what you did with it.
The atomic ratio in this salt is 1:1. The mass ratio is 22.999:35.457 of sodium to chlorine, the ratio of the atomic weights of sodium and chlorine.
Yes. Smaller salt grains will dissolve more quickly as they present a larger surface area-to-volume ratio.
2:1
The ratio of salt water to fresh water on the Earth is approximately 40 to 1. The oceans are comprised of salt water.
You think probable to concentration of salt in water.
Adding one mole of salt raises the boiling point of the water more than adding one mole of sugar to the water
This is because the mole fraction of water in salt solution is lower than the mole fraction of water in pure water and salt is not volatile - has no appreciable vapour presure. This is an instance of Raoult's Law in action. In very simple terms the number of water molecules at the surface of the water is less when there is salt present thus lowering its vapour presure.
The density of a salt water solution compared against the densities of "pure" water and salt provides an approximate value of the ratio of water to salt in the mixture.
sugar is a covalent compound where as salt is an ionic compound,so salt while dissolving in the water splits.This is mainly dependent of the 'total dissolved partical' concentration (mol/L):Sugar (C6H12O6): 1 mole particles per 180 g (for 1 mole sugar)Salt (NaCl) 2 mole particles per 58.5 g (for 1 mole salt) = 6 mole particles per about 180In water the freezing point will be lowered by 1.86oC per mole particles dissolved: So 180 g/L sugar: freeze at -1.86oCand 175.5 g/L salt freeze at -(6*1.86) = -11.2oCor 29.2 g/L salt will freeze at the same as 180 g suger: -1.86oC
sollution with a 1 to 1 ratio of salt to water
You need to add more water so that the salt to water ratio is less Mehwesh T
salt and water
Safe ratio would be 75 mil of Acid to 1 Litre of Water
yes, if enough fresh water was added it could dissolve the salt. evaporation would not work though. the salt would stay and the water turns into vapor in the air leaving a higher salt : air ratio. ++++ The first sentence is wrong. The salt is ALREADY dissolved! The water turns into vapour at it surface and leaves the salt behind. There is no "salt:air ratio".