The complete ionic equation is:Cu^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + 2OH^-(aq) =>Cu(OH)2(s) + 2Na^+(aq) + 2NO3^-(aq)
The net ionic equation is:
Cu^2+(aq) + 2OH^-(aq) => Cu(OH)2(s)
2 NaOH + Co(NO3)2 ----> Co(OH)2 + 2 NaNO3
Co2+ + OH- ----> Co(OH)2
The products are Sodium Nitrate and Copper Hydroxide.
This is a double-replacement reaction. The charges of each cation and anion are:Copper (II): 2+Nitrate: 1-Sodium: 1+Hydroxide: 1-This means that the equation without coefficients would beCu(NO3)2 + NaOH --> NaNO3 + Cu(OH)2.Since there is an uneven number of nitrates and hydroxides, coefficients must be added before NaOH and NaNO3 to make the equation balanced.Cu(NO3)2 + 2NaOH --> 2NaNO3 + Cu(OH)2
Al(NO3)3 + 4NaOH -> NaAlO2 + 3NaNO3 + 2H2O
Word equation: Sodium Hydroxide + Calcium Nitrate --> Calcium Hydroxide + Sodium Nitrate Chemical equation: Ca(NO3)2 + 2NaOH --> Ca(OH)2 + 2NaNo3
the equation for sodium nitrate and copper III iodide can be given below.Cu I 2 +2 Na No3 ->I (NO3)2 + 2NaI. this is the balance reaction for the above.
The products are Sodium Nitrate and Copper Hydroxide.
Copper(II) hydroxide and sodium nitrate are thermally decomposed to oxides by heating.
When heat copper hydroxide and sodium Nitrate the pale blue precipitate change into black solid
when they react, it forms copper hydroxide which is insoluble, and hence a precipitate in the resultant solution of sodium nitrate
Solutions of copper (II) compounds will undergo precipitation reactions with sodium hydroxide solution when mixed together to produce a bright blue precipitate of copper (II) hydroxide and a solution of a sodium salt.The chemical equations for the reaction between Copper (II) nitrate and Sodium hydroxide are as follows:Cu(NO3)2 (aq) + 2NaOH (aq) → Cu(OH)2 (s) + 2NaNO3 (aq)Copper II nitrate + sodium hydroxide → copper II hydroxide + sodium nitrate
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3
you make a black precipitate.
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
This is a double-replacement reaction. The charges of each cation and anion are:Copper (II): 2+Nitrate: 1-Sodium: 1+Hydroxide: 1-This means that the equation without coefficients would beCu(NO3)2 + NaOH --> NaNO3 + Cu(OH)2.Since there is an uneven number of nitrates and hydroxides, coefficients must be added before NaOH and NaNO3 to make the equation balanced.Cu(NO3)2 + 2NaOH --> 2NaNO3 + Cu(OH)2
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
Al(NO3)3 + 4NaOH -> NaAlO2 + 3NaNO3 + 2H2O