Aluminium Hydroxide or in other terms Al(OH)3
Al4C3 +12H2O = 4Al(OH)3 + 3CH4
You need to know the separate concentrations of the different substances in order to find the volume necessary
The molar mass of aluminium hyroxide is approximately 78 g/mol.
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
Al(OH)3
Aluminium hydroxide - Al(OH)3
Aluminium Hydroxide or in other terms Al(OH)3
Al4C3 +12H2O = 4Al(OH)3 + 3CH4
Al(OH)3 Indicates that there are three OH groups per Al metal
Al(OH)3 is a base (Aluminum hyroxide)
You need to know the separate concentrations of the different substances in order to find the volume necessary
The molar mass of aluminium hyroxide is approximately 78 g/mol.
Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation Al2SO43 CaOH2 - AlOH3 CaSO4. B. H3BO3 - H4B6O11 H2O C. NaOH Cl2 - NaCl NaClO H2O. D. Al O2- Al2O3. E. PCl5 H2O - HCl H3PO" is a 8.9 balanced equation
That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3
Aluminum forms a +3 ion, and hydroxide's formula is OH-, so the formula for aluminum hydroxide would be: Al(OH)3
this equation is wrong, it should be Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 +CaSO4 and when balanced, it is Al2(SO4)3 + 3Ca(OH)2 --> 2Al(OH)3 +3CaSO4