Ag+1 (aq) + Cl-1 (aq) -> AgCl (s).
The reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) results in the formation of silver chloride (AgCl) which is insoluble. Thus, the net ionic equation isAg^+(aq) + Cl^-(aq) ==> AgCl(s)
Ag+ + NO-3 + Na+ + Cl----------NaNO3 (aq) + AgCl (white precipitate)
It would come out to Ag^+ + Cl^- = AgCl Remember solubility rules nitrate and Ca both are soluble therefore they are not in the final equation.
the solution changes to a white percipitate. Ionic Equation= Ag(+) + 2Cl(-) -----> AgCl(2) === ===
Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) --> Na+(aq) + NO3-(aq) + AgCl(s)
The reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) results in the formation of silver chloride (AgCl) which is insoluble. Thus, the net ionic equation isAg^+(aq) + Cl^-(aq) ==> AgCl(s)
Ag+(aq) + Cl-(aq) --> AgCl(s)
Silver Nitrate + Sodium Chloride --> Silver Chloride + Sodium Nitrate AgNO3 + NaCl --> AgCl + NaNO3 The four ionic equations are: AgNO3 --> Ag+ + NO3- NaCl --> Na+ + Cl- Ag+ + Cl- --> AgCl Na+ + NO3- --> NaNO3 Since the oxidation states of all four ions present in the equation don't change before or after the reaction. Therefore, I don't think there's a net ionic equation. The reaction above is just a displacement or precipitation (AgCl is insoluble, therefore it forms a white precipitate after the reaction) reaction.
Ag+ + NO-3 + Na+ + Cl----------NaNO3 (aq) + AgCl (white precipitate)
There is none because they cancel out.
It would come out to Ag^+ + Cl^- = AgCl Remember solubility rules nitrate and Ca both are soluble therefore they are not in the final equation.
Ag+ + (NO3)- + Na+ + Cl- = Na+ + (NO3)- + AgCl(s)
Since both chloride anions and nitrate anions have a charge of -1, there will be the same number of moles of silver chloride produced as the moles of silver nitrate reacted. (Since both silver nitrate and silver chloride are ionic compounds, it would be preferable to call their "moles" "formula units" instead.)
the solution changes to a white percipitate. Ionic Equation= Ag(+) + 2Cl(-) -----> AgCl(2) === ===
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
Ag+(aq) + NO3-(aq) + Na+(aq) + Cl-(aq) --> Na+(aq) + NO3-(aq) + AgCl(s)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3