This equation is simply 2 OH-1 (aq) + 2 H+1 (aq) -> 2 H2O.
OH- + 2H+ -> 2H2O(l)
There is no reaction for this process.H2SO4 + NaCl => N.R.
2koh + h2so4 --> k2so4 + 2h2o
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
2ki+ h2so4 ----> k2so4 + 2hi
Answer this question… OH- + 2H+ 2H2O(l)
There is no reaction for this process.H2SO4 + NaCl => N.R.
2koh + h2so4 --> k2so4 + 2h2o
2KHCO3(aq) + H2SO4(aq) [bidirectional arrows] K2SO4(aq) + 2CO2(g) + 2H2O(l)
H2SO4 + 2KOH = K2SO4 + 2H2O
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
2K+ + OH- + 2H+ + SO42- 2H2O(l) + 2K+ + SO4 2-
2ki+ h2so4 ----> k2so4 + 2hi
H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
H2so4+2koh=k2so4+2h2o
2KOH + H2SO4 = K2SO4 + 2H2O
If is K2O (potassium oxide) it would be: K2O+H2SO4=K2SO4+H2O It could also form potassium bisulfate: K2O + 2 H2SO4 = 2 KHSO4 + H2O But I'm not sure if you are referring to potassium peroxide (K2O2) or superoxide (KO2)