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Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
White precipitate will formed which is barium sulfate.
Yes it is soluble in water
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
The products will be potassium sulfate and water.
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Barium sulfate is the precipitate
White precipitate will formed which is barium sulfate.
Yes it is soluble in water
The barium ion in barium hydroxide and sulfate ion in sulfuric acid combine to form barium sulfate, which is insoluble in water.
Iron Sulphate + Sodium Hydroxide -> Sodium Sulphate (Na2SO4) and Iron Hydroxide (Fe(OH)2)
The reactions of sodium hydroxide and calcium hydroxide with sulfuric acid will produce sodium sulfate and calcium sulfate respectively (water will be another product in both reactions. Sodium sulfate is soluble in water and so will remain in solution. Calcium sulfate, however, is insoluble and will precipitate as a solid.
The products will be potassium sulfate and water.
A balanced equation MUST have EQUAL numbers of EACH type of atom on BOTH sides of the arrow.The correctly balanced equation is:The equation for sodium hydroxide and aluminum sulfate is written as follows.Al2(SO4)3(s) + 6 NaOH(aq) 2 Al(OH)3(s) + 6 Na+(aq) + 3 SO42–(aq)
To remove any remaining sodium sulfate or sodium hydroxide.
2Fe(SO4)3 + 6KOH ---> 2Fe(OH)3 + 3K2(SO4) iron 3 is +3, sulfate is -2, potasium is +1, and hydroxide is -1
Put drops of Sodium, Potassium, or Ammonium Hydroxide in it. The Cupric hydroxide will precipitate out in blue colour. Dont put excess hydroxide or there will be a formation of another intense blue complex compound