The normality of 98 g of sulfuric acid in 500 mL of solution is 4 N
The normality of 98 g of sulfuric acid in 500 mL of solution is 98G/Mol = 220g H2SO4
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Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
To prepare the Liebermann-Burchard reagent you add 200 ml of cold acetic anhydride and 200 ml of glacial acetic acid at room temperature to a 500 ml amber glass bottle that has a polyseal cap. Turn the bottle upside down to mix the solution then add 30 ml of cold concentrated sulfuric acid.
To prepare 1M sulphuric acid from concentrated sulphuric acid:First consider the molecular weight of H2SO4 = 98 g/mol, so you have to add 98g of conc. acid and make up to 1 liter of water (as pointed out at the 4thpoint).Considering that acid is a liquid, you should also consider density: where density = mass/volume, which is said on the bottle to be (about) 1.84 g/mL,so then you have: volume = 98g / 1.84(g/mL) = 53.2 mLNow you have to consider the acid purity, usually 98% then you have to do this: 53.2 mL if the acid were 100% pure convert in mL given with the purity of 98%, so 100% x 53.2 mL / 98% = 54.3 mL of (98%) concentrated acid.Finally CAREFULLY add this 54.3 mL (or 98 g, cf. first point) to about 0.9 L dist. water while continuously stirring (evolving heat!), and after that fill it up to 1.00 L with also dist. water. Never reverse this: DO NOT add water to concentrated fluids!
675
pipette out 8.5 ml perchloric acid in to 500 ml acetic acid and add 21 ml of acetic anhydride make up to volume to 1000 ml with acetic acid*. * Let this solution stand for one day and check the water content
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
500
To prepare the Liebermann-Burchard reagent you add 200 ml of cold acetic anhydride and 200 ml of glacial acetic acid at room temperature to a 500 ml amber glass bottle that has a polyseal cap. Turn the bottle upside down to mix the solution then add 30 ml of cold concentrated sulfuric acid.
To prepare 1M sulphuric acid from concentrated sulphuric acid:First consider the molecular weight of H2SO4 = 98 g/mol, so you have to add 98g of conc. acid and make up to 1 liter of water (as pointed out at the 4thpoint).Considering that acid is a liquid, you should also consider density: where density = mass/volume, which is said on the bottle to be (about) 1.84 g/mL,so then you have: volume = 98g / 1.84(g/mL) = 53.2 mLNow you have to consider the acid purity, usually 98% then you have to do this: 53.2 mL if the acid were 100% pure convert in mL given with the purity of 98%, so 100% x 53.2 mL / 98% = 54.3 mL of (98%) concentrated acid.Finally CAREFULLY add this 54.3 mL (or 98 g, cf. first point) to about 0.9 L dist. water while continuously stirring (evolving heat!), and after that fill it up to 1.00 L with also dist. water. Never reverse this: DO NOT add water to concentrated fluids!
675
pipette out 8.5 ml perchloric acid in to 500 ml acetic acid and add 21 ml of acetic anhydride make up to volume to 1000 ml with acetic acid*. * Let this solution stand for one day and check the water content
pipette out 8.5 ml perchloric acid in to 500 ml acetic acid and add 21 ml of acetic anhydride make up to volume to 1000 ml with acetic acid.Stand iday this solution and and check the water content not exceedsto 0.025 to 0.5% then standardize the solution by PHP
C1V1 = C2V2 (500ml)(1M) = (Xml)(6M) ( divide both sides by 6 in this case ) = 83.3ml Put this 83.3ml of 6M acid into a 600ml beaker and add 416.7ml to get 500ml total.
The question is describing the planet Venus, which shows up in our sky sometimes as an "evening star" and sometimes as a "morning star".
In order to prepare 500 ppm of lead solution from lead nitrate dissolve 0.799 gm of lead nitrate in 1000ml of water--add 1 or 2 drops of nitric acid.
for NaOH normality = molarity ; hence for 1M(1N) solution you have to dissolve 40 g NaOH in 1L water ...... therfore for 0.1 N soln you have to dissolve 4 g in 1 L water and then standerized it with acid which has known normality
MW of H2SO4 is 98.08. 2M = 2 x 98.08 in 1 L of water (1 gram=1 ml). Take 500 ml water in a 1 L measuring cylinder. Add 196.16 ml slowly along the side into water in the measuring cylinder. Use 50 ml pipette with automated pipettor. If needed you may want to keep the cylinder in ice to take care of the heat generated. Then make up to volume to 1 L with water. Eq. wt for H2SO4 = 98.08/2 = 49.039. SO for 2N solution, 2 eq.wt in 1 L. 98.08 ml in 1 L water adopting the method cited above.