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607 x 1 mol / 83.8 = 7.24 mol

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Q: What is the number of moles in 607 g krypton?
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Find the number of moles in 607 g krypton?

7.24 moles.


What is the number of moles of argon in 607 g of argon?

the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles


How many grams are contained in 4.56 moles of krypton Kr?

4.56 moles Kr x 83.798 g/mole = 382.119 grams = 382 grams (to 3 significant figures)NOTE: You should not use more than 3 significant figures since 4.56 moles limits the precision. Thus the answers of 381.66g and 382.1188 g are incorrect.


How is a number of moles of an element determined from a known mass?

The number of moles is mass in g/molar mass in g.


If you have g of beryllium how many moles is this equivalent to?

The formula is: number of moles = g Be/9,012.


What is the number of moles in 0.025 g NH42Cr2O7?

The number of moles 9,92.10e-5.


What is the number of moles in 15 g of As H3?

0.0027 moles.


How many moles of SO2 are present in 250.0 g?

Number of moles is determined by dividing molar mass into the number of grams. SO2 has a molar mass of 64.066 g. To find the number of moles in 250.0 g of SO2, divide 250.0 g by 64.066 g. This gives you just over 3.9 moles.


What is the number of moles if you have 22.99 g of C28H44O?

22.99 g of C28H44O is equal to 0,058 moles.


What is the number of moles in 510 g of Al2S3?

510 g Al2S3 is equal to 3,396 moles.


What volume will 0.405 g of krypton gas occupy at STP?

First we need the moles of krypton gas. Monoatomic gas.0.405 grams Kr (1 mole Kr/83.80 grams)= 0.004833 moles krypton gas======================Now the ideal gas equation.PV = nRT(1 atm)(X volume) = (0.004833 moles Kr)(0.08206 L*atm/mol*K)(298.15 K)= 0.118 Liters of krypton gas--------------------------------------


How many moles of argon in 607 g of argon?

Have: 607gAr Need: Moles of Argon From the periodic table we know that there are 39.948gAr per every 1 mole of Argon. 607g/39.948 = your answer.