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All you do is take the total number of ions in the compound and multiply it by the molarity to calculate the osmolarity.

Thus,

0.12 * 3 = 0.36

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12y ago
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7y ago

CaCl2 ==> Ca^2+ + 2Cl^-
osmolarity = 3 x 0.450 = 1.35 osmolar

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Q: What is the osmolarity of a 0.12M CaCl2 solution?
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