1 mol/L sodium chloride is equal to 2 osmol/L.
NaCl is generally added to the nutrient media for maintaining the Osmotic pressure. Maintaining osmotic pressure is important, because, increase or decrease in the osmotic pressure leads to cell burst or death due to the effect of osmosis. So, maintaining the osmotic pressure is done by adding correct amount of NaCl.
NaCl--table salt--is typically look at as the solid solute within a solution. The osmotic pressure you need is for the solvent which will need to be calculated I believe. The Van Hoff Factor for NaCl (1.9) is probably what you needed
The solution of NaCl with the concentration 0,9 % is considered normal saline; the osmotic pressure is equal to the pressure in the cells.
This a saline solution with the concentration of 0,9 g NaCl/100 mL distilled water. This is a isotonic solution; the meaning is that the osmotic pressure of the this solution is equal to the osmotic pressure of the blood serum.
Osmotic pressure of saline (0.91% NaCl w/v) is arround 0.0085 ATM.The osmotic pressure is 7.58 ATM at 25 °C. P=MRT The molarity of 0.9% NaCl is 0.155M. But it has 2 ions per formula so 0.31 mol/L * 0.082 latm/Kmol * 298K= 7.58 ATM
Both solutions give rise to the same osmotic pressure.
The osmotic coefficient of sodium chloride is 0,93.
Seven seas
Nothing. NaCl creates a reverse reaction to H2O.
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
NaCl+H2O COMPELATE THE EQUATION
NaCL + H2O