In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
Potassium's oxidation number is +1. Chromium's oxidation number is +6. Oxygen's oxidation number is -2.
In Cr2O72- chromium (Cr) has an oxidation number of 6+ while oxygen has an oxidation number of 2-.
+6
1
In CrBr (chromium monobromide) Cr would have an oxidation number of +1. This compound is not known perhaps you meant CrBr3, where chromium has an oxidation number of +3
In Cr2O72- chromium (Cr) has an oxidation number of 6+ while oxygen has an oxidation number of 2-.
Potassium's oxidation number is +1. Chromium's oxidation number is +6. Oxygen's oxidation number is -2.
1
+6
It is true for chromium. But O shows 2asthe oxidation number.
The possible oxidation numbers for iron cations are +2 and +3. Oxygen in oxyanions is usually assigned an oxidation number of -2, producing a total negative charge of -14 for the seven oxygen atoms in a dichromate anion. If the iron cation has an oxidation number of +2, the two chromium atoms must have a total oxidation number of +12, which is possible when each chromium atom has an oxidation number of +6. An iron (III) cation would require the chromium atoms to have a non integral charge, which is not possible since electrons with half charges are not known. Therefore, the oxidation number of iron in the compound is +2 and the oxidation number for chromium is +6.
The oxidation number of chromium varies from +2 to +6.
The oxidation number of a compound is zero (nitrogen -3, hydrogen +1, chromium +3, oxygen -2).
The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.
Potassium dichroamte is K2Cr2O7, in the dichroamte ion both Cr atoms have an oxidation number of +6.
Hi, CrO5 is a compound which has the structure which has peroxide linkage(O2 2-) as shown: Thus the oxidation number of Chromium can be calculated as : Let the oxidation number of Cr be x, then x-2-2(2)=0 x-2-4=0 x-6=0 thus x=+6