The oxidation number for chromium can vary depending on the compound it is part of. In general, chromium can have oxidation states ranging from -2 to +6.
In K₂CrO₄, the oxidation number of potassium (K) is +1, and the oxidation number of oxygen (O) is -2. Since the compound is neutral, the oxidation number of chromium (Cr) can be calculated as follows: 2(+1) + Cr + 4(-2) = 0. Solving for chromium, the oxidation number of chromium in K₂CrO₄ is +6.
The oxidation number of chromium changes from +6 in Na2Cr2O7 to +3 in CrCl3. This represents a reduction in oxidation number by three units.
The oxidation number of phosphorus in chromium(III) phosphate is +5. In chromium(III) phosphate, each chromium ion has a +3 oxidation state, and the overall compound is electrically neutral, so the oxidation number of phosphorus must be +5 to balance the charges.
The oxidation number of chromium in CrBr2 is +2. This is because bromine typically has an oxidation number of -1 and there are two bromine atoms in CrBr2, leading to a total oxidation number of -2. The oxidation number of chromium must therefore be +2 to balance the charges.
The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.
In K₂CrO₄, the oxidation number of potassium (K) is +1, and the oxidation number of oxygen (O) is -2. Since the compound is neutral, the oxidation number of chromium (Cr) can be calculated as follows: 2(+1) + Cr + 4(-2) = 0. Solving for chromium, the oxidation number of chromium in K₂CrO₄ is +6.
The oxidation number of chromium changes from +6 in Na2Cr2O7 to +3 in CrCl3. This represents a reduction in oxidation number by three units.
The oxidation number of phosphorus in chromium(III) phosphate is +5. In chromium(III) phosphate, each chromium ion has a +3 oxidation state, and the overall compound is electrically neutral, so the oxidation number of phosphorus must be +5 to balance the charges.
The oxidation number of chromium in CrBr2 is +2. This is because bromine typically has an oxidation number of -1 and there are two bromine atoms in CrBr2, leading to a total oxidation number of -2. The oxidation number of chromium must therefore be +2 to balance the charges.
It is true for chromium. But O shows 2asthe oxidation number.
The oxidation number of chromium in K2Cr2O7 is +6. Each potassium ion has an oxidation state of +1, and each oxygen atom has an oxidation state of -2. By setting up an equation based on the overall charge of the compound, it can be determined that chromium has an oxidation state of +6.
In CrO3, the oxidation number of chromium (Cr) is +6 and the oxidation number of oxygen (O) is -2. This is because oxygen typically has an oxidation number of -2, and there are three oxygen atoms in CrO3 to give a total charge of -6. To balance the charge, the chromium atom must have an oxidation number of +6.
In chromium(III) oxide, the oxidation number of chromium is +3 and the oxidation number of oxygen is -2. This compound has the chemical formula Cr2O3.
The oxidation number of chromium in potassium dichromate is +6. Each oxygen has an oxidation number of -2, and since the compound is neutral, the oxidation number of potassium is +1. This means the two chromium atoms in potassium dichromate each have an oxidation number of +6 to balance the charges.
The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.
The oxidation number of chromium (Cr) in CrO4^2- is +6. Since each oxygen atom has an oxidation number of -2, and the overall charge of the polyatomic ion is -2, the oxidation number of chromium can be determined by solving the equation: (oxidation number of Cr) + 4(-2) = -2.
The oxidation number of one chromium atom in potassium dichromate (K2Cr2O7) is +6. This is because each oxygen atom has an oxidation number of -2 and each potassium atom has an oxidation number of +1, so the overall charge of the compound is zero, making the oxidation number of chromium +6 to balance it out.