It is true for chromium. But O shows 2asthe oxidation number.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.
+6 for Cr, -2 for each O in Cr2O72-oxidation number for oxygen is -2 so 7 of them makes -14 in total but the compound has an overall charge of 2- so therefore +12 is required. As there are two chromium then the oxidation number for each one is +6
The oxidation number of chromium in Cr2O7 is +7. The oxidation number of oxygen is -2, so 7 O atoms times -2 = -14. In order to balance the -14 on the oxygen atom, each chromium atom must have an oxidation number of +7, because 2 Cr atoms times +7 equals +14.
The answer is + 6 The way I figured it out was that O has a -2 charge. -2 times 7 is - 14. to leave -2 you need a +12 charge. So you divide 12 by 2 because you have 2 Cr and you get 6
+2 for Ca, +6 for Cr, -2 for each O
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
The oxidation number for hydrogen (H) is typically +1. Therefore, the total oxidation number for 6 hydrogen atoms would be +6.
The oxidation number of Cr in MgCrO4 is +6. This is because oxygen is typically assigned an oxidation number of -2, and the overall charge of the compound is 0, so the oxidation number of magnesium (+2) and oxygen (-2) must be balanced by the oxidation number of Cr (+6).
Sulphur has 6 valence electrons. So its maximum oxidation number is +6.