The oxidation number for the dihydrogen phosphate ion (H2PO4-) is +1 for each hydrogen atom, -2 for the oxygen atom, and +5 for the phosphorus atom.
To find the oxidation number of phosphorus in phosphate (PO4), consider that oxygen typically has an oxidation number of -2. Since there are four oxygen atoms in phosphate, their total charge is -8. The overall charge of the phosphate ion is -3, so the oxidation number of phosphorus can be calculated as +5 to balance the charges.
The ionic compound formed from NaH2PO4 is sodium dihydrogen phosphate. In this compound, the sodium ion has a +1 charge, and the dihydrogen phosphate ion (H2PO4-) has a -1 charge.
The sum of the oxidation numbers in the phosphate ion (PO4^3-) is -3. Each oxygen atom has an oxidation number of -2, totaling -8. The oxidation number for phosphorus is +5 to offset the oxygen atoms and give a total charge of -3 for the ion.
NaH2PO4(aq) --> Na+(aq) + H2PO4(aq)sodium dihydrogen phosphate --> sodium ion + dihydrogen phosphate ionExplanationDissociation is the breakdown of soluble salts into their respective ions. Sodium dihydrogen phosphate is made up of two ions - sodium and dihydrogen phosphate. Therefore the dissociation of sodium dihydrogen phosphate will produce sodium and dihydrogen phosphate ions.
The oxidation number of phosphorus in a hydrogen phosphate ion (HPO4^2-) is +5. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms surrounding the phosphorus atom, giving it an oxidation number of +5 to balance the negative charge of the oxygens.
The chemical formula for dihydrogen phosphate ion is H2PO4-
The dihydrogen phosphate ion - (H2PO4)-is an anion.
To find the oxidation number of phosphorus in phosphate (PO4), consider that oxygen typically has an oxidation number of -2. Since there are four oxygen atoms in phosphate, their total charge is -8. The overall charge of the phosphate ion is -3, so the oxidation number of phosphorus can be calculated as +5 to balance the charges.
The ionic compound formed from NaH2PO4 is sodium dihydrogen phosphate. In this compound, the sodium ion has a +1 charge, and the dihydrogen phosphate ion (H2PO4-) has a -1 charge.
The sum of the oxidation numbers in the phosphate ion (PO4^3-) is -3. Each oxygen atom has an oxidation number of -2, totaling -8. The oxidation number for phosphorus is +5 to offset the oxygen atoms and give a total charge of -3 for the ion.
NaH2PO4(aq) --> Na+(aq) + H2PO4(aq)sodium dihydrogen phosphate --> sodium ion + dihydrogen phosphate ionExplanationDissociation is the breakdown of soluble salts into their respective ions. Sodium dihydrogen phosphate is made up of two ions - sodium and dihydrogen phosphate. Therefore the dissociation of sodium dihydrogen phosphate will produce sodium and dihydrogen phosphate ions.
The answer is 81 protons.
The oxidation number of phosphorus in a hydrogen phosphate ion (HPO4^2-) is +5. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms surrounding the phosphorus atom, giving it an oxidation number of +5 to balance the negative charge of the oxygens.
The oxidation state for the phosphate ion (PO4) is -3. This is because oxygen typically has an oxidation state of -2 and there are four oxygen atoms in the phosphate ion. The oxidation state of phosphorus in the phosphate ion is therefore calculated as +3 to balance out the -8 charge from the four oxygen atoms.
P = +5 PO4^3- = -3 4(-2) + p = -3 P =5
Those are chemical formulas. NH4 is the ammonium polyatomic ion, and PO4 is the phosphate polyatomic ion. Ammonium has a +1 charge and phosphate has a -3 charge.
In disodium phosphate (Na2HPO4), each sodium (Na) atom has an oxidation number of +1 since it is in Group 1 of the periodic table. The hydrogen atom (H) has an oxidation number of +1, and the phosphate ion (PO4) as a whole has a charge of -3, making the phosphorus atom (P) have an oxidation number of +5.