I think it is -1
Na2[Fe(CN)5NO]·2H2O, the oxidation number of iron is +3.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
CN- group has an overall charge of -1. C has oxidation of +2 and N -3 in CN since N has more negativity than C. In other words, N competes and wins with C when both try to take electrons to satisfy their need to become stable. Cheers.
Cr(CN)2
I think it is -1
Na2[Fe(CN)5NO]·2H2O, the oxidation number of iron is +3.
a)3 b)2 c)1 d)4 Fe is the transitional metal K3[Fe(CN)6] , we know that Potassium, K, has an oxidation number of +1 The oxidation number of CN= -1, so 6*CN has an oxidation number of -6 so therefore Fe - 6 = -3 Fe = -3 + 6 = +3 The oxidation number of Fe is +3. so A
in oxidation reaction addition of electron occurs.
CN- group has an overall charge of -1. C has oxidation of +2 and N -3 in CN since N has more negativity than C. In other words, N competes and wins with C when both try to take electrons to satisfy their need to become stable. Cheers.
Cr(CN)2
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
Zn has oxidation number +2; S has oxidation number -2
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Oxidation number of Si is +4.Oxidation number of O is -2.