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+1 for each hydrogen

-2 for each oxygen

+6 for each sulphur

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Q: What is the oxidation number of H2 S O4?
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In the compound H2 S hydrogen has an oxidation number of 1 plus and sulfur has an oxidation number of?

2-


What is the oxidation number of S in H2 S?

+8.H2 has an oxidation of +1 (A total of +2)O5 has an oxidation of -2 (A total of -10).We do not know anything about the oxidation of S, so since we know H2SO5 isn't a complex ion, we can assume the overall oxidation number is 0.Therefore, the oxidation number of S = Oxidation of O5 - Oxidation number of H2.Since 10 - 2 = 8, Oxidation number of S is 8.(no, it did not)Sorry,Sulphur cannot have more than +6 oxidation number as it belongs to VI(A) group.In H2SO5, one peroxide bond is present. i.e., the oxidation number of 2 oxygen atoms is -2. (Compare hydrogen peroxide, H2O2)2 atoms of oxygen will get -1 oxidation number each. The remaining 3 atoms will have +2 oxidation number each. This is a special case. Oxidation number of each hydrogen atom is +1 only.So, finally the oxidation number of Sulphur is +6. [(+2)+(+6)+(-8) = 0]Hope you got it. (yes, it did so)


In the reaction 2Al plus 3H2SO4 Al2SO43 plus 3H2 in the products has an oxidation number of 0?

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