-2 for O
+1 for Na
+6 for S
The oxidation state for oxygen in this compound is 2-, as it is for most oxygen compounds.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
- 2 for each O, +3 for each Ni
In VO vanadium has an oxidation number of +2 and O an oxidation number of -2 Just in case you missed the 2+ , in vanadyl ion VO2+ V has the oxidation number of +4, O has -2
Ru has oxidation number +8, O has oxidation number of -2
The oxidation state for oxygen in this compound is 2-, as it is for most oxygen compounds.
0 because all compounds have an oxidation number of 0. It's the ions (fe S O) that have oxidation numbers, The sum of these oxidation numbers always = 0 in a compound and hence a compound has a oxidation number of 0. :-) hope this helped....
- 2 for each O, +3 for each Ni
In VO vanadium has an oxidation number of +2 and O an oxidation number of -2 Just in case you missed the 2+ , in vanadyl ion VO2+ V has the oxidation number of +4, O has -2
+2 for Mg -2 for O
Ru has oxidation number +8, O has oxidation number of -2
Nitrogen has the oxidation number of +IV and oxygen atoms mark as -II.
The oxidation number of alkaline earth metals in compounds is usually +2.
The overall oxidation number is -2 so the average oxidation number of O is -1.
O.S. of H = +1 O.S. of O = -2 O.N. of cpd = 0
Oxidation number of chlorine is +7. oxidation number of O is -2.
On the face of it without knowing the structure it would be -2 however that would imply an oxidation number for Cs of +6. Fortunately this compound does not exist which explains the weird oxidation number for Cs. There is a compound Cs11O3 and we get a fractional oxidation number of 6/11- Cs11O3 must contain some Cs-Cs bonding.