answersLogoWhite

0


Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: What is the oxidation of each ion in the compound MgBr2?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the oxidation number of each ion in MgBr2?

Magnesium is a divalent cation, with oxidation number +2, and bromide is a monovalent anion, with oxidation number -1 for each of the two ions. Thus the compound is electrically neutral.


What compound is MgBr2?

An ionic compound, as it contains a metal ion "Mg2+" and a non metal ion "Br-".


What is the oxidation state of cl in clo2?

This is a gas compound. Chlorine shows +4 as the oxidation number.


What compound has an oxidation number 5?

Phosphorus in PCl5 Nitrogen in Nitrate (NO3-) ion


What must the sum of the oxidation number be equal to?

It must be equal to the charge on the compound/ion


What is the oxidation number of S in the compound Na2 SO4?

This is a ionic compound too. Sulfur shows +6 in sulfate ion.


What is the oxidation number of Li in Li Al H4?

This contains H- ion. Li shows +1 oxidation number.


What is the oxidation state of SO42?

In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-


What compound has the formula PO 3plus?

PO3+ is the formula of an ion known as Phosphoryl ion. Here Phosphorus is in +5 oxidation state.


How is HPO4 is formed?

That's not a stable compound. If you meant HPO4--, it can be formed by either the reduction of the PO43- ion or oxidation of the H2PO4- ion.


What is the oxidation number of platinum tetracloride?

Platinum tetrachloride - PtCl4 The oxidation number is not of platinum tetrachloride but of the platinum ion in this compound - equal to 4+.


How do you find the oxidation numbers?

For a neutral atom or compound, the oxidation number is always 0. For an ion, the overall oxidation number is its charge. If you need to find an oxidation number to a particular atom of a compound, there are two ways: working out the Lewis structures or balancing the charges.